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AlexFokin [52]
3 years ago
13

Mercury has a density of 13.6 g/mL. How many milliliters of mercury have a mass of 350 g? *

Chemistry
1 answer:
Colt1911 [192]3 years ago
7 0

solution:

density x volume=mass volume x volume

13.6gml x 3.55ml

thus,the object has a mass of 98.3g

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Arrange the colors of visible light, green, red, and blue, in order of increasing wavelength.
lukranit [14]

Answer: The increasing wavelength of colors:

Red > Green > Blue

Explanation:

Wavelength: This is the property of wave which includes the distance between two consecutive crests or trough. This is denoted by the Greek letter Lambda and it is found by dividing the velocity of the wave with its frequency.

Wavelength of colours are

Violet: 400 - 420 nm

Indigo: 420 - 440 nm

Blue: 440 - 490 nm

Green: 490 - 570 nm

Yellow: 570 - 585 nm

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8 0
3 years ago
You use 50.00 mL of a 12.0 M solution of HCl solution to make a 500.00 mL solution. What is the concentration of the new solutio
Alexandra [31]

Answer:

1.2 M

Explanation:

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6 0
3 years ago
The height of a column of mercury in a closed-end manometer is 13.2 cm. What is the pressure of the gas in torr
AlladinOne [14]

Answer:

P_{gas}=131.96torr

Explanation:

Helo,

In this case, the pressure must be computed as follows:

P_{gas}=gh\rho _{Hg}

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P_{gas}=9.8\frac{m}{s^2}*(13.2cm *\frac{1m}{100cm} )*(13.6\frac{g}{cm^3}*\frac{1kg}{1000g}*\frac{1x10^6cm^3}{1m^3} )\\\\P_{gas}=17592.96Pa*\frac{760torr}{101325Pa} \\\\P_{gas}=131.96torr

Best regards.

5 0
3 years ago
What properties are those that describe what happens when a substance reacts with another substance? catalyst properties chemica
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5 0
4 years ago
Read 2 more answers
If a substance has a half life of 58 years and starts with 500 g radioactive, how much remains radioactive after 30 years?
Vilka [71]

Answer:

A = 349 g.

Explanation:

Hello there!

In this case, since the radioactive decay kinetic model is based on the first-order kinetics whose integrated rate law is:

A=Ao*exp(-kt)

We can firstly calculate the rate constant given the half-life as shown below:

k=\frac{ln(2)}{t_{1/2}} =\frac{ln(2)}{58year}=0.012year^{-1}

Therefore, we can next plug in the rate constant, elapsed time and initial mass of the radioactive to obtain:

A=500g*exp(-0.012year^{-1} *30year)\\\\A=349g

Regards!

5 0
3 years ago
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