Group 17 is the most readily reduced elements on the periodic table, meaning that they are so close to being a stable elements, only missing 1 electron to complete their valance electron shell. Thus they will essentially react with anything to get that last electron!
Group 1 elements are extremely reactive because they are the most readily oxidized, they are very close to reaching stability by giving up only 1 electron. Thus they will react with almost anything to give up their electron.
Explanation:
A chemical reaction is one in which a chemical change occurs.
During a chemical change;
- The process is irreversible
- New kinds of matter produced
- There is a change in mass
Based on these premise;
Baking cake batter is a chemical reaction because you cannot reverse the process
Shredding a paper is not a chemical reaction because no new kind of matter is produced.
Twisting of a metal wire is not a chemical reaction
Yellowing of newspaper in sunlight is a chemical change. The process cannot be reversed
The elements are identified by the number of protons of the atom, which is its atomic number.
In this case the number of protons 39 (atomic number 39) permit you to identify the element as gallium.
Now, to identify the isotope you tell the name of the element and add the mass number.
The mass number is the sum of the protons and the neutrons
In this case, the number of neutrons is the original 39 plus the 2 added suddenly, i.e. 39 + 2 = 41, so the mass number is 31 + 41 = 72
Therefore, the isotope is gallium - 72.
Answer: isotope gallium - 72
It seems like I begin to forget whole organic Chemistry. Anyway, the answer is 2-methylheptane-3-yne.
To build a name for this molecule, you need to:
1. Determine where there is the lowest chain beginning with the double, triple bond, or there is other thing for other types of organic molecules.. In this case you have one triplet bond, and the lowest chain there is the one that is below the bond.
2. In this small chain you see one "forks": CH3 and another CH3 go from the one CH. Put number 1 where there are the most number of such compounds, in this case it doesn't matter because we have one CH3 in one way and one CH3 in the another.
3. Determine the largest chain which surely has the triple bond. Put the numbers from 2 to the final beginning with CH3 where you put number 1. Your largest chain consists of 7 particles CH3, CH2, and CH.
4. You see that you also have one unnamed particle, the one which is "the other way" when you are in the CH which is below the triple bond on the picture. Its name will be 2-methyl because it is connected with particle #2 and it consists only of one carbon. If there were 2, it would be ethyl, and so on.
5. Finally, let's write a full name: put 2-methyl first, "2-methyl." Then, write a full name for the chain of 7 carbons, which has to be heptane, if it had 5, you would name it pentane, ethane, and so on. So, we have "2-methylheptane." Finally, you see that you have a triple bond after the carbon #3. Put a dash and the number of this carbon. "2-methylheptane-3" you should have. Since it is alkyne (organic molecule with one triple bond), you have to write "yne" at the end.
the final name is "2-methylheptane-3-yne." You can answer the question "explain your naming process" by using the answer I provided. Hope it helps. Good luck!
I think the answer is C. C and D