1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Rus_ich [418]
3 years ago
13

The empirical formula of glucose is CH2O, and the molecular formula of glucose is 6 times than the empirical formula. What is th

e molecular formula of glucose?
Chemistry
1 answer:
goldfiish [28.3K]3 years ago
3 0
C6H12O6
That is the molecular formula of glucose
You might be interested in
On average, Earth’s crust contains about 8.1% aluminum by mass. If a standard 12-ounce soft drink can contains approximately 15
MrMuchimi

Answer:

5400 cans

Explanation:

First we convert the total weight, 1 ton, to grams:

1ton=1x10^{6}g

Now we need to know the mass of aluminum:

m_{Al}=\frac{10^{6}*8.1}{100} =81000g

Now we make the relation between the mass of aluminum in 1 ton of the earth's crust and the mass of aluminum per can:

n=\frac{81000g}{15g/can} =5400cans

8 0
3 years ago
What is the molarity of a solution in which 25g NaCl in a 2.00 L solution?
Paladinen [302]

Mass of sodium :- 23 grams

Mass of Chlorine :- 35.5 grams

Mass of NaCl :- 58.5 grams

mass given :- 25 grams

moles :- 0.432 ( given mass/ ionic mass)

molarity =   \frac{moles}{vol}  \\ molarity =  \frac{0.432}{2}  \\ molarity = 0.216 \: mole{l}^{ - 1} or \: molar

5 0
2 years ago
What mass of iron is formed when 10 grams of carbon react with 80 grams of iron iii oxide?
yKpoI14uk [10]

Answer:

55.85 grams of Fe is formed.

Explanation:

Identify the reaction:

2Fe₂O₃  +  3C  →  4Fe  +  3CO₂

Identify the limiting reactant, previously determine the mol of each reactant

(mass / molar mass)

10 g / 12 g/m = 0.83 moles C

80 g / 159.7 g /m = 0.500 moles Fe₂O₃

2 moles of oxide need 3 moles of C, to react

0.5 moles of oxide, will need ( 0.5  . 3)/ 2 = 0.751 mol

I have 0.83 moles of C, so C is the excess.

The limiting is the oxide.

3 mol of C need 2 mol of oxide to react

0.83 mol of C, will need (0.83  . 2)/ 3 = 0.553 mol of oxide, and I only have 0.5 (That's why Fe₂O₃ is the limiting)

Ratio is 2:4 (double)

If I have 0.5 moles of oxide, I will produce the double, in the reaction.

1 mol of Fe, will be produce so its mass is 55.85 g

5 0
3 years ago
Grams of cl in 38g of cf3cl
Lerok [7]

Answer:

114 grams

Explanation:

3chlorines per compound*38grams=114

8 0
3 years ago
C como Se define una cuenca hidrogatica<br><br>Ayudaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa<br><br><br><br>​
sladkih [1.3K]

Answer:

Una cuenca es un área de tierra que drena todos los arroyos y la lluvia a una salida común, como la salida de un embalse, la boca de una bahía o cualquier punto a lo largo del canal de un arroyo.

Explanation:

Espero que esto ayude a marcar el MÁS CEREBRAL !!!

7 0
3 years ago
Other questions:
  • PLEASE HELP I'M STUCK
    9·2 answers
  • Select the compounds that cannot undergo friedel crafts alkylation. check all that apply. check all that apply. aniline phenol k
    11·1 answer
  • How is the tempature related to phsyical change
    10·1 answer
  • What happens to an egg that is not fertilized?
    6·2 answers
  • A neutralization reaction is a _________ replacement reaction that starts with an ________ and a __________ and ends with ______
    14·1 answer
  • The absorption spectrum of a molecular compound in the microwave radiation range provides information about the: 1.Electronic st
    5·1 answer
  • Can someone answer 1<br> For me please?
    5·1 answer
  • When you have a molecule that has one side with access to electrons, and one side that is deficient in electrons, a(n) ______ fo
    13·1 answer
  • An exergonic reaction __________ free energy, and an endergonic reaction __________ free energy.
    13·1 answer
  • A gas effuses 4.0 times faster than oxygen (o2). what is the molecular mass of the gas? 1.0 g/mol 1.0 g/mol 2.0 g/mol 2.0 g/mol
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!