Answer:
Plane will 741.6959 m apart after 1.7 hour
Explanation:
We have given time = 1.7 hr
So if we draw the vectors of a 2d graph we see that the difference in angles is = 
Speed of first plane = 730 m/h
So distance traveled by first plane = 730×1.7 = 1241 m
Speed of second plane = 590 m/hr
So distance traveled by second plane = 590×1.7 = 1003 m
We represent these distances as two sides of the triangle, and the distance between the planes as the side opposing the angle 58.6.
Using the law of cosine, 
representing the distance between the planes, we see that:
r = 741.6959 m
KE = 2000 J
Explanation:
KE = (1/2)mv^2
= (1/2)(0.100 kg)(200 m/s)^2
= 2000 J
They have the same velocity because their displacements (shortest line from point A to point B, which is a straight line) are the same and they meet at the same time.
Answer:
<h3>The answer is 12 m/s²</h3>
Explanation:
The acceleration of an object given it's mass and the force acting on it can be found by using the formula
f is the force
m is the mass
From the question we have
We have the final answer as
<h3>12 m/s²</h3>
Hope this helps you
Answer:
0.2448 point²
Explanation:
1 gry = 1/10 line
1 line = 1/12 inch
=> 1 gry in inches = 1/10 * 1/12 = 1/120 inch
=> 1 inch = 120 gry
1 point = 1/72 inch
=> 1 inch = 72 points
Therefore,
120 gry = 72 points
=> 1 gry = 3/5 point
Therefore,
1 gry² = (3/5)² point²
1 gry² = 9/25 point²
This means that 0.68 gry² will be:
0.68 gry² = 0.68 * 9/25 point²
=> 0.68 gry² = 0.2448 point²
