Answer:
When it's closest to the sun.
Explanation:
The force of gravity acting on a planet is equal to its mass times its centripetal acceleration.
Fg = m v^2 / r
The force of gravity is defined by Newton's law of universal gravitation as:
Fg = mMG / r^2
Therefore:
mMG / r^2 = m v^2 / r
MG / r = v^2
v increases as r decreases. So the planet is moving fastest when it's closest to the sun, also known as the <em>perihelion</em>.
Answer:
<h2>7.5 N</h2>
Explanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question
mass = 2.5 kg
acceleration = 3.0 m/s²
We have
force = 2.5 × 3.0 = 7.5
We have the final answer as
<h3>7.5 N</h3>
Hope this helps you
Answer:
hope it helps......
Explanation:
Pressure, in the physical sciences, the perpendicular force per unit area, or the stress at a point within a confined fluid.
Answer:
![9.56\cdot 10^{-7} C](https://tex.z-dn.net/?f=9.56%5Ccdot%2010%5E%7B-7%7D%20C)
Explanation:
A parallel-plate capacitors consist of two parallel plates charged with opposite charge.
Since the distance between the plates (1 cm) is very small compared to the side of the plates (19 cm), we can consider these two plates as two infinite sheets of charge.
The electric field between two infinite sheets with opposite charge is:
![E=\frac{\sigma}{\epsilon_0}](https://tex.z-dn.net/?f=E%3D%5Cfrac%7B%5Csigma%7D%7B%5Cepsilon_0%7D)
where
is the surface charge density, where
Q is the charge on the plate
A is the area of the plate
is the vacuum permittivity
In this problem:
- The side of one plate is
L = 19 cm = 0.19 m
So the area is
![A=L^2=(0.19)^2=0.036m^2](https://tex.z-dn.net/?f=A%3DL%5E2%3D%280.19%29%5E2%3D0.036m%5E2)
Here we want to find the maximum charge that can be stored on the plates such that the value of the electric field does not overcome:
![E=3\cdot 10^6 N/C](https://tex.z-dn.net/?f=E%3D3%5Ccdot%2010%5E6%20N%2FC)
Substituting this value into the previous formula and re-arranging it for Q, we find the charge:
![E=\frac{Q}{A\epsilon_0}\\Q=EA\epsilon_0 = (3\cdot 10^6)(0.036)(8.85\cdot 10^{-12})=9.56\cdot 10^{-7} C](https://tex.z-dn.net/?f=E%3D%5Cfrac%7BQ%7D%7BA%5Cepsilon_0%7D%5C%5CQ%3DEA%5Cepsilon_0%20%3D%20%283%5Ccdot%2010%5E6%29%280.036%29%288.85%5Ccdot%2010%5E%7B-12%7D%29%3D9.56%5Ccdot%2010%5E%7B-7%7D%20C)