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Sauron [17]
4 years ago
9

What is one way you could reduce the friction between two surfaces

Physics
1 answer:
Vlad [161]4 years ago
6 0
You could put ice, put it on wheels!
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Explain the term "avalanche state"
vagabundo [1.1K]

Answer:

The downwind side of an obstacle such as a ridge. The addition of weight on top of a snowpack, usually from precipitation, wind drifting, or a person. An avalanche that releases from a point and spreads downhill collecting more snow - different from a slab avalanche. Also called a point-release or sluff.

Explanation:

5 0
3 years ago
When an object is at rest, it might have several forces acting on it. however,?
SSSSS [86.1K]
For the object to be moving, there must be a value for the forces acting on this object in a certain direction to cause the object to move.

On the other hand, when an object is at rest, despite the possibility of having several forces acting on it, these forces balance out to a net force of zero which keeps the body still with no motion.
4 0
3 years ago
A dog runs 50 meters north 40 meters east and 20 meters south what is the displacement
Allisa [31]
So....
imagine the x and y axis or draw it on a piece of paper, a white board or even on your wall if you like. I'm kidding just draw it on a piece of paper

50m up and 20m down 
the dog's displacement is 50 - 20 which is 30
your answer is 30m north
3 0
3 years ago
An electron is released from rest at the negative plate of a parallel plate capacitor. The charge per unit area on each plate is
amm1812

Answer:1.066\times 10^7 m/s

Explanation:

Given

Charge per unit area on each plate(\sigma)=2.2\times 10^{-7}

Plate separation(y)=0.013 m

and velocity is given by

v^2-u^2=2ay

where a=acceleration is given by

a=\frac{F}{m}=\frac{eE}{m}

e=charge on electron

E=electric field

m=mass of electron

E=\frac{\sigma }{\epsilon _0}

a=\frac{e\sigma }{m\epsilon _0}

substituting values

v=sqrt{\frac{2e\sigma y}{m\epsilon _0}}

v=\sqrt{\frac{2\times 1.6\times 10^{-19}\times 2.2\times 10^{-7}\times 0.013}{9.1\times 10^{-31}\times 8.85\times 10^{-12}}}

v=1.066\times 10^7 m/s

4 0
3 years ago
Charge is given in microcoulombs. What must you multiply the charge by to use Coulomb's
iVinArrow [24]

Answer:

Option A. 10¯⁶

Explanation:

To know which option is correct, we must bear in mind, the relationship between micro coulomb (μC) and coulomb (C). This is given below:

Recall:

1 μC = 10¯⁶ C

Therefore, to convert micro coulomb (μC) to coulomb (C), multiply the value given in micro coulomb (μC) by 10¯⁶.

Thus, option A gives the correct answer to the question.

7 0
3 years ago
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