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o-na [289]
3 years ago
15

2 AICI3 + 3 Ca - 3 CaCl2 + 2 Al

Chemistry
1 answer:
Ivanshal [37]3 years ago
8 0
50 grams of calcium
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Manganese(iv) oxide reacts with aluminum to form elemental manganese and aluminum oxide: 3mno2+4al→3mn+2al2o3part awhat mass of
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<span>12.4 g First, calculate the molar masses by looking up the atomic weights of all involved elements. Atomic weight manganese = 54.938044 Atomic weight oxygen = 15.999 Atomic weight aluminium = 26.981539 Molar mass MnO2 = 54.938044 + 2 * 15.999 = 86.936044 g/mol Now determine the number of moles of MnO2 we have 30.0 g / 86.936044 g/mol = 0.345081265 mol Looking at the balanced equation 3MnO2+4Al→3Mn+2Al2O3 it's obvious that for every 3 moles of MnO2, it takes 4 moles of Al. So 0.345081265 mol / 3 * 4 = 0.460108353 mol So we need 0.460108353 moles of Al to perform the reaction. Now multiply by the atomic weight of aluminum. 0.460108353 mol * 26.981539 g/mol = 12.41443146 g Finally, round to 3 significant figures, giving 12.4 g</span>
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4 years ago
Help me, it’s pretty easy science moon stuff !
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Based on the information I received reading the picture, the answer should be “B”

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Answer : The correct option is, pressure.

Explanation :

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The value of 'R' has several different values which are :

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Hence, the correct option is, pressure.

3 0
3 years ago
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