2 AICI3 + 3 Ca - 3 CaCl2 + 2 Al

147 J is what kind of quantity

ioda

Answer:

quantitative data

Explanation:

hope this helped

3 0

4 years ago

one million atoms of a particular element have a mass of 1.99 ×10^-17 grams. how many moles of this element are there?

Marianna [84]

(1.99x10^-17) x 1000000
= 1.99x10^-11 (1.99x10^-11) / (6.023x10^23)
= 3.304001328x10^-35
hope this helps

4 0

3 years ago

X-x/4-1/3=2+x/4 please answer me

Karo-lina-s [1.5K]

Answer:

x= 14/3 = 4.667

Explanation:

X - X/4 - 1/3 = 2 + X/4

7 0

3 years ago

The concentration of a biomolecule insdie a rod-shaped prokaryotic cell is 0.0051 M. Calculate the number of molecule inside the

Ann [662]

Answer: The number of molecules inside the cell are $2.2\times 10^6$

Explanation:

We are given a prokaryotic cell, which is in the shape of rod or cylinder.

The equation used to calculate the volume of cylinder is:

$V=\pi r^2h$

where,

V = volume of cell = ?

r = radius of the celle = $\frac{d}{2}=\frac{1.7\mu m}{2}=0.85\mu m=8.5\times 10^{-7}m$ (Conversion factor: $1m=10^6\mu m$ )

h = length of the cell = $3.1\mu m=3.1\times 10^{-6}m$

Putting values in above equation, we get:

$V=(3.14)\times (8.5\times 10^{-7})^2\times 3.1\times 10^{-6}\\\\V=7.033\times 10^{-18}m^3$

To calculate the number of moles for given molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Molarity of biomolecule = 0.0051 M

Volume of solution = $7.033\times 10^{-18}m^3=7.033\times 10^{-15}L$ (Conversion factor: $1m^3=1000L$ )

Putting values in above equation, we get:

$0.0051M=\frac{\text{Moles of biomoleculel}}{7.033\times 10^{-15}L}\\\\\text{Moles of biomolecule}=(0.0051mol/L\times 7.033\times 10^{-15}L)=3.59\times 10^{-17}mol$

According to mole concept:

1 mole of a compound contains $6.022\times 10^{23}$ number of molecules

So, $3.59\times 10^{-17}$ moles of a biomolecule will contain = $(3.59\times 10^{-17}\times 6.022\times 10^{23}=2.2\times 10^6$ number of molecules

Hence, the number of molecules inside the cell are $2.2\times 10^6$

5 0

3 years ago

Calculate the empirical formula of a compound that is 42.9% Carbon and 57.1% Oxygen.

Marrrta [24]

Answer:

CO.

Explanation:

Assuming the given percentages are by mass, we can solve this problem via imagining we have 100 g of the compound, if that were the case we would have:

42.9 g of C

57.1 g of O

Now we convert those masses into moles, using the elements' respective molar masses:

42.9 g of C ÷ 12 g/mol = 3.57 mol C

57.1 g of O ÷ 16 g/mol = 3.58 mol O

As the number of C moles and O moles is roughly the same, the empirical formula for the compound is CO.

4 0

3 years ago