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yKpoI14uk [10]
3 years ago
9

4.05 kg + 567.95 g + 100.1 g add the correct value using the correct sig figs and or least precise degree of precision. When i d

id least degree of precision i got 4718.1g, do we need to convert the kg unit to grams before getting the least degree of precision? since i used 100.1 as dop and if i had converted first the dop of 4.05 or now 4050g the dop is now only to the tens place compared to being in the tenths place
Chemistry
1 answer:
daser333 [38]3 years ago
6 0

To find the least degree of precision we swould model it after the kg amount or 4.05 kg or two decimal places. So that would add 0.56795 kg (0.57 kg) and then 0.1001 kg (0.1 kg) so that our answer would be 4.72 kg.

<span>In the other hand, the greatest degree of precision would be to conver 4.05 kg to 4050 g so that 4050g + 567.95 + 100.1 g= 4718.05 grams or 4718 g.</span>

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What is the new concentration of 25.0mL added to 125.0mL of 0.150M
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Answer:

The new concentration is 0.125 M.

Explanation:

Given data:

Initial volume V₁ = 125.0 mL

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New volume V₂ = 25 mL +125 mL = 150 mL

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If 50 g of lead (of specific heat 0.11 kcal/kg ∙ C°) at 100°C is put into 75 g of water (of specific heat 1.0 kcal/kg ∙ C°) at 0
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As we know that,  

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

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where,

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m_2 = mass of water = 75 g

T_{final} = final temperature = ?

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Now put all the given values in equation (1), we get

50\times 0.11\times (T_{final}-373)=-[75\times 1.0\times (T_{final}-273)]

T_{final}=279.8K

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3 0
3 years ago
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