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yKpoI14uk [10]
3 years ago
9

4.05 kg + 567.95 g + 100.1 g add the correct value using the correct sig figs and or least precise degree of precision. When i d

id least degree of precision i got 4718.1g, do we need to convert the kg unit to grams before getting the least degree of precision? since i used 100.1 as dop and if i had converted first the dop of 4.05 or now 4050g the dop is now only to the tens place compared to being in the tenths place
Chemistry
1 answer:
daser333 [38]3 years ago
6 0

To find the least degree of precision we swould model it after the kg amount or 4.05 kg or two decimal places. So that would add 0.56795 kg (0.57 kg) and then 0.1001 kg (0.1 kg) so that our answer would be 4.72 kg.

<span>In the other hand, the greatest degree of precision would be to conver 4.05 kg to 4050 g so that 4050g + 567.95 + 100.1 g= 4718.05 grams or 4718 g.</span>

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An acetic acid buffer solution is required to have a pH of 5.27. You have a solution that contains 0.010 mol of Acetic acid. Wha
dlinn [17]

Answer:

Molarity of sodium acetate you will need to add is 0.0324M

Explanation:

<em>Assuming volume of the buffer is 1L.</em>

<em />

The pH of a buffer can be determined using Henderson-Hasselbalch equation:

pH = pKa + log [A⁻] / [HA]

<em>Where pKa is pKa of the weak acid,  [A⁻] molar concentration of conjugate base and [HA] molar concentration of weak acid</em>

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Replacing for the acetic buffer (pKa = 4.76):

pH = 4.76 + log [Sodium Acetate] / [Acetic Acid]

As you have 0.010 moles of acetic acid in 1L:

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And you require a pH of 5.27:

5.27 = 4.76 + log [Sodium Acetate] / [0.010M]

0.51 = log [Sodium Acetate] / [0.010M]

10^0.51 = [Sodium Acetate] / [0.010M]

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3.236 [0.010M] = [Sodium Acetate]

0.0324M = [Sodium Acetate]

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3 years ago
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masha68 [24]
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Sliva [168]

Answer:

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