3 years ago

Calculate the pH of a 0.22 M ethylamine solution.

Chemistry

2 answers:

zheka24 [161]3 years ago

5 0

Answer:

pH = 10.1

Explanation:

For weak base solutions [OH] = SqrRt([Base]·Kb

Then, from pH + pOH = 14 => pH = 14 - pOH

[OH} = SqrRt[(0.22)(5.6 x 10⁻⁴)] = 3.91

pH = 14 - 3.91 = 10.1

evablogger [386]3 years ago

4 0

Answer:

answer is 12.18

Explanation:

(C2H5NH2, Kb = 5.6 x 10-4.)

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