Answer:
1) 0.1667
2) 0.8333
3) 1
Step-by-step explanation:
Let A be the event that 3 is observed on the first trial.
Let B be the event that at least two trials are required to observe a 3
a) A six-sided die has 6 possible outcomes of 1,2,3,4,5,6
3 is one of the six possible outcomes
P(A) = no of favourable outcomes /no of possible outcomes
P(A) = 1/6 = 0.1667
b) The event of requiring at least two trials to observe a 3 is the event of not observing a 3 on the first trial.
P(B) = P(A')
P(A')= 1 - P(A)
P(B) = 1 - 1/6
= 5/6 = 0.8333
c) P(AnB) = P(A) + P(B)
= 1/6 + 5/6
= 6/6 = 1
Answer:
Exact-$1,536 Estimate-$1,500
Step-by-step explanation:
26+22=48
48 x 32 = 1,536
Estimate-1,500 or 1,540
Exact-1,536
That would be 25 units. You can draw it out and you would get 25 units, or you could see the difference in -10 and 15, their distance would be 25 units.
That made no sense.
The factors of 66 are 1, 2, 3, 6, 11, 22, 33, and 66. Out of these factors, the greatest factor of 66. The next highest factor other than 66 is 33. A number which is three more than 33 is 33 + 3 = 36.
Answer:
<h3>(6x²-11x) is the right answer.</h3>
