Answer: the formation of ester is an exothermic reaction.. therefore, decreasing the temperature will make the reaction proceed forward, producing more esters
Explanation:
We can use the heat
equation,
<span>Q = mcΔT
</span>
Where Q is the amount
of energy transferred (J), m is the mass of the substance (kg), c is the
specific heat (J g⁻¹ °C⁻¹) and ΔT is the temperature difference (°C).
In this problem there is no any data about initial temperature of the water. So, we can assume that given temperature of 5.2 °C as the temperature difference.
Q = 348 J
m = ?
c = 4.186 J g⁻¹ °C⁻¹
ΔT = 5.2 °C<span>
By applying the formula,
348 J = m x </span>4.186 J g⁻¹ °C⁻¹ x 5.2 °C<span>
m = 15.99 g
Hence, the grams of water is 15.99.</span>
Moles of Na_2O
- Given mass/Molar mass
- 35/62
- 0.56mol
2 mols Na_2O produces 1 mol sodium carbonate.
1 mol sodium oxide produces 0.5mol sodium carbonate
Moles of sodium carbonate
Molar mass
- 2(23)+12+3(16)
- 46+12+48
- 106g/mol
Mass
Answer:
So, 10 mole of water will weigh (18x10) = 180g.
