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3 years ago

How should the baking of a pizza be categorized

Chemistry

2 answers:

romanna [79]3 years ago

8 0

Answer:

The correct answer is endothermic process.

Explanation:

An endothermic process is one in which the system absorbs heat from the environment. In the pizza baking process, the dough absorbs the heat from the oven. The flow of heat goes from the oven to the pizza. In this case, it is about thermal energy, if the temperature of a body increases, the thermal energy of the body also does it.

Have a nice day!

MrMuchimi3 years ago

3 0

<h2>The baking of a Pizza be Categorize as Endothermic Process</h2>

The baking of a pizza should be categorized as an endothermic process because the dough absorbs heat. An endothermic process is a method that absorbs energy from its surroundings which is habitually in the form of energy.

It can be a biochemical process like solving the salt in water or just the melting of ice. Therefore, the dough absorbs heat and it is categorized as an endothermic process.

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The number of moles of oxygen in the gas is 1.5 L.

The correct option is (A).

<h3>What are moles? </h3>

The mole is the International System of Units' foundation unit of material quantity.

Given,

The volume of gas is 33.6 L

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Temperature is 0°C

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By formula of moles, volume is divided by molar mass

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4 years ago

When 4.21 grams of potassium hydroxide are added to 250 mL of water in a coffee cup calorimeter, the temperature rises by 4.14°C

Schach [20]

Answer:

The molar heat of solution of potassium hydroxide = 57.7 kJ /mol

Explanation:

<u>Step 1:</u> Data given

Mass of potassium hydroxide = 4.21 grams

Volume of water = 250 mL

Temperature rise = 4.14 °C

Density = 1g/mL

Specific heat = 4.184 J/g°C

<u>Step 2:</u> Calculate the heat absorbed by water

q = m*c*ΔT

⇒ with m = the mass of water = 250 grams

⇒ with c= the specific heat of the solution = 4.184 J/g°C

⇒ with ΔT = 4.14 °C

q = 250 * 4.184*4.14 = 4330.4 J

<u>Step 3:</u> Calculate moles of KOH

Moles KOH = Mass KOH / Molar mass KOH

Moles KOH = 4.21 grams / 56.106 g/mol

Moles KOH = 0.075 moles

<u>Step 4:</u> Calculate molar heat of solution

4330.4 J / 0.075 moles = 57738.7 j/mol = 57.7 kJ /mol

(Note that the enthalpy change for the reaction is negative because the reaction is exothermic)

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