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Brut [27]
3 years ago
14

A sample of gas at 3000.0mmHg inside a steel tank is cooled from 500.0°C to 0.00°C what is the final pressure of the gas in the

steel tank
Chemistry
1 answer:
Andrej [43]3 years ago
5 0

Answer:

1429.32 mmHg

Explanation:

Initial Pressure P1 = 3000.0mmHg

Initial Temperature T1 = 500.0°C + 273 = 573 K ( Converting to kelvin temperature)

Final Temperature T2 = 0.00°C + 273 = 273 K ( Converting to kelvin temperature)

Final Pressure P2 = ?

The pressure of a given amount of gas is directly proportional to the absolute temperature provided volume remains constant.

This is given by the mathematical expression;

P1 / T1  = P2 / T2

Inserting the values;

3000 / 573 = P2 / 273

P2 = 273 * 3000 / 573

P2 = 1429.32 mmHg

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Answer:

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3 years ago
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Heavy nuclides with too few neutrons to be in the band of stability are most likely to decay by what mode?
Margarita [4]

Answer:

Positron emission

Explanation:

Positron emission involves the conversion of a proton to a neutron. This process increases the mass number of the daughter nucleus by 1 while its atomic number remains the same. The new neutron increases the number of neutrons present in the daughter nucleus hence the process increases the N/P ratio.

A positron is usually ejected in the process together with an anti-neutrino to balance the spins.

6 0
3 years ago
What is the mass of 0.28 mol of iron
maria [59]
Mass = number of mol x molar mass
Mass = 0.28mol x 55.8g/mol
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5 0
3 years ago
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A piece of unknown metal with mass 30 g is heated to 110.0 °C and dropped into 100.0 g of water at 20.0 °C. The final temperatur
Ymorist [56]

<u>Answer:</u> The specific heat of metal is 0.821 J/g°C

<u>Explanation:</u>

When metal is dipped in water, the amount of heat released by metal will be equal to the amount of heat absorbed by water.

Heat_{\text{absorbed}}=Heat_{\text{released}}

The equation used to calculate heat released or absorbed follows:

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]       ......(1)

where,

q = heat absorbed or released

m_1 = mass of metal = 30 g

m_2 = mass of water = 100 g

T_{final} = final temperature = 25°C

T_1 = initial temperature of metal = 110°C

T_2 = initial temperature of water = 20.0°C

c_1 = specific heat of metal = ?

c_2 = specific heat of water = 4.186 J/g°C

Putting values in equation 1, we get:

30\times c_1\times (25-110)=-[100\times 4.186\times (25-20)]

c_1=0.821J/g^oC

Hence, the specific heat of metal is 0.821 J/g°C

8 0
3 years ago
Which of the following has a mass of 10.0 g?
Serjik [45]

Answer:

a.  0.119mol Kr

Explanation:

To solve this problem, we must understand that;

     Mass  = number of moles x molar mass

Molar mass of Kr  = 83.3g/mol

                        Ar = 40g/mol

                        He = 4g/mol

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a0.119 mol Kr               mass  = 0.119 x 83.3 = 9.9g

b 0.400 mol Ar             mass  = 0.4 x 40  = 16g

C 1.25 mol He               mass  = 1.25 x 4  = 5g

d 2.02 mol Ne              mass  = 2.02 x 20.18  = 40.8

Krypton is the answer

5 0
3 years ago
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