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murzikaleks [220]
1 year ago
10

ch3)2c(oh)ch2ch3 skeletal structure, Functional groups, compound type & alcohol class if it’s an alcohol

Chemistry
1 answer:
xxTIMURxx [149]1 year ago
6 0

The skeletal structure of an organic compound is an abbreviated representation of its molecular structure, they are quick and easy to draw.

For example, the following image shows the skeletal structure of a compound:

The peaks represent the carbons. We must remember that carbon can have a maximum of 4 bonds.

Now, I will show you how is the structure of this specific compound:

This is ternary alcohol, called 2-methyl-2-butanol. If you see carefully, you will notice that each carbon has 4 bonds. The functional groups present will be OH. The skeletal structure will be:

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Can someone please show me how to do problem number 4? Please show work so I can try to understand it. Thanks!
larisa86 [58]
With the given formula, we can calculate the amount of CO₂ using the balance equation but we first need the moles of CH₄

1) to find the moles of CH₄, we need to use the ideal gas formula (PV= nRT). if we solve for n, we solve for the moles of CH₄, and then we can convert to CO₂. Remember that the units put in this formula depending on the R value units. I remember 0.0821 which means pressure (P) has to be in atm, volume (V) in liters, the amount (n) in moles, and temperature (T) in kelvin.

PV= nRT

P= 1.00 atm
V= 32.0 Liters
n= ?
R= 0.0821 atm L/mol K
T= 25 C= 298 K

let plug the values into the formula.

(1.00 x 32.0 L)= n x 0.0821 x 298K

n= (1.00 x 32.0 L )/ (0.0821 x 298)= 1.31 moles CH₄

2) now let's convert the mole of CH₄ to moles to CO₂ using the balance equation

1.31 mol CH₄ (1 mol CO₂/ 1 mol CH₄)= 1.31 mol CO₂

3) Now let's convert from moles to grams using the molar mass of CO₂ (find the mass of each atom in the periodic table and add them)

molar mass CO₂= 12.00 + (2 x 16.0)= 44.0 g/mol

1.31 mol CO₂ ( 44.0 g/ 1 mol)= 57.6 g CO₂

Note: let me know if you any question.



5 0
3 years ago
A student made a graph to show the chemical equilibrium position of a reaction.
pogonyaev

Answer:

Concentration, because the amounts of reactants and products remain constant after equilibrium is reached.

Explanation:

The rate of reaction refers to the amount of reactants converted or products formed per unit time.

As the reaction progresses, reactions are converted into products. This continues until equilibrium is attained in a closed system.

When equilibrium is attained, the rate of forward reaction is equal to the rate of reverse reaction, hence the concentration of reactants and products in the system remain fairly constant over time.

When deducing the rate of reaction, concentration of the specie of interest is plotted on the y-axis against time on the x-axis.

8 0
3 years ago
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