Answer:
The percent recovery from re crystallization for both compounds A and B is 69.745 and 81.44 % respectively.
Explanation:
Mass of compound A in a mixture = 119 mg
Mass of compound A after re-crystallization = 83 mg
Percent recovery from re-crystallization :

Percent recovery of compound A:

Mass of compound B in a mixture = 97 mg
Mass of compound B after re-crystallization = 79 mg
Percent recovery of compound B:

Answer:
The entropy and the systems surrounding it tend to increase.
Answer:
8
Explanation:
You are going to divide the 24 moles of H by the moles of H used in Ammonia. In this case 3
24/3=8