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zubka84 [21]
2 years ago
11

There are 5.0g of I-131 left after 40 days. How many grams were in the original sample if the half-life is 8 days?

Chemistry
1 answer:
Gre4nikov [31]2 years ago
5 0
5.0=mo(1/2) ^ 5
5.0=mo (.031)
about 160/161.29
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Which of the following two combinations of reactants is more appropriate for the preparation of p-nitrophenyl phenyl ether? Fluo
VladimirAG [237]

Answer:

p-fluoronitrobenzene and sodium phenoxide is more appropriate

Explanation:

An ipso substitution is required to form p-nitrophenyl phenyl ether.

For this ipso substitution, an alkoxide anion needs to attack as a nucleophile at the carbon atom attached to fluorine atom and thereby substitute that F atom.

p-nitrophenoxide is an weak nucleophile as compared to phenoxide due to presence of electron withdrawing resonating effect of nitro group at para position.

p-fluoronitrobenzene is a good choice for nucleophilic attack by alkoxide anion as compared to fluorobenzene due to higher positive charge density at carbon atom directly attached to F atom. Higher positive charge density arises due to presence of electron withdrawing resonating effect og nitro group at para position.

So, p-fluoronitrobenzene and sodium phenoxide is more appropriate

5 0
3 years ago
You use a _______ when you are changing compounds
zvonat [6]

Answer:

snetence

Explanation:

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3 0
2 years ago
4.41 g of propane gas (C3H8) is injected into a bomb calorimeter and ignited with excess oxygen, according to the reaction below
gayaneshka [121]

Answer :  The heat of the reaction is -221.6 kJ

Explanation :

Heat released by the reaction = Heat absorbed by the calorimeter

q_{rxn}=-q_{cal}

q_{cal}=c_{cal}\times \Delta T

where,

q_{rxn} = heat released by the reaction = ?

q_{cal} = heat absorbed by the calorimeter

c_{cal} = specific heat of calorimeter = 97.1kJ/^oC=97100J/^oC

\Delta T = change in temperature = (T_{final}-T_{initial})=(27.282-25.000)=2.282^oC

Now put all the given values in the above formula, we get:

q_{cal}=(97100J/^oC)\times (2.282^oC)

q_{cal}=221582.2J=221.6kJ

As, q_{rxn}=-q_{cal}

So, q_{rxn}=-221.6kJ

Thus, the heat of the reaction is -221.6 kJ

6 0
3 years ago
Write a net ionic equation to show that benzoic acid, C6H5COOH, behaves as a Brønsted-Lowry acid in water.
Nitella [24]

Answer:

H⁺(aq) + H₂O(l) ⇄ H₃O⁺(aq)

Explanation:

According to Brönsted-Lowry acid-base theory, an acid is a substance that donates H⁺. Let's consider the molecular equation showing that benzoic acid is a Brönsted-Lowry acid.

C₆H₅COOH(aq) + H₂O(l) ⇄ C₆H₅COO⁻(aq) + H₃O⁺(aq)

The complete ionic equation includes all the ions and molecular species.

C₆H₅COO⁻(aq) + H⁺(aq) + H₂O(l) ⇄ C₆H₅COO⁻(aq) + H₃O⁺(aq)

The net ionic equation includes only the ions that participate in the reaction and the molecular species.

H⁺(aq) + H₂O(l) ⇄ H₃O⁺(aq)

5 0
3 years ago
I KNOW THE ANS JUST NEED AN EXPLANATION...PLEASE I WILL Mark you the brainiest
Reika [66]
I’m pretty sure it would be D.
5 0
2 years ago
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