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Sati [7]
3 years ago
10

Dos cargas iguales de 10^-7C estan separadas por una distancia de 2m. calcule la fuerza con que se repelen

Physics
1 answer:
m_a_m_a [10]3 years ago
8 0

Answer:

F=2.25\times 10^{-5}\ N

Explanation:

According to question,

Charge 1 and charge 2 are 10^{-7}\ C

The distance between charges is 2 m

We need to find the force with which two positive charges repel. It is called electrostatic force of repulsion. It can be given by :

F=\dfrac{kq^2}{r^2}\\\\F=\dfrac{9\times 10^9\times (10^{-7})^2}{2^2}\\\\F=2.25\times 10^{-5}\ N

So, the electric force of repulsion is 2.25\times 10^{-5}\ N.

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A proton is moved from a position where the electric potential is 125 V to a position where the electric potential is 275 V. The
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The force that attracts earth to an object is equal to and opposite the force that earth exerts on the object. Explain why earth
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