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3 years ago

What is the empirical formula of C6H18O3? CH3O C2H5O C2H6O C2H5O5

Chemistry

2 answers:

denis-greek [22]3 years ago

6 0

What is the empirical formula of C6H18O3?

CH3O

C2H5O

C2H6O CORRECT ANSWER

C2H5O5

I took the test and C) was correct

andreyandreev [35.5K]3 years ago

3 0

So to find the empirical formula you have to simplify. What is something you can take out of all three? The number three, so divide everything by three leaving you with (C2H6O). I hope this helped!

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Given that 10.00mL of 0.1894M CH3COOH was titrated with 0.2006M NaOH in this experiment, calculate the volume, in mL, of NaOH re

sertanlavr [38]

Answer:

$V_{base}=9.442mL$

Explanation:

Hello!

In this case, when acetic acid is titrated with sodium hydroxide, the following chemical reaction is carried out:

$CH_3COOH+NaOH\rightarrow CH_3COONa+H_2O$

Whereas there is a 1:1 mole ratio between the acid and the base, which means that at the equivalence point we evidence:

$n_{acid}=n_{base}$

Which in terms of volumes and concentrations is written as:

$M_{acid}V_{acid}=M_{base}V_{base}$

Thus, solving for the required volume of base, we obtain:

$V_{base}=\frac{M_{acid}V_{acid}}{M_{base}}=\frac{0.1894M*10.00mL}{0.2006M}\\\\ V_{base}=9.442mL$

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3 years ago

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Explanation:

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3 years ago

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nasty-shy [4]

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Explanation:

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3 years ago

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Arturiano [62]

Answer:

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3 years ago

solution is 2.41 molal toluene (C 7H 8, 92 g/mol) in benzene (C 6H 6, 78 g/mol); i.e. consider toluene the solute, benzene the s

inn [45]

Answer : The molarity of solution is, 1.73 mole/L

Explanation :

The relation between the molarity, molality and the density of the solution is,

where,

$d=M[\frac{1}{m}+\frac{M_b}{1000}]$

d = density of solution = $0.876g/cm^3=0.876g/mL$

m = molality of solution = 2.41 mol/kg

M = molarity of solution = ?

$M_b$ = molar mass of solute (toluene) = 92 g/mole

Now put all the given values in the above formula, we get the molality of the solution.

$0.876g/ml=M\times [\frac{1}{2.41mol/kg}+\frac{92g/mole}{1000}]$

$M=1.73mol/L$

Therefore, the molarity of solution is, 1.73 mole/L

7 0

3 years ago