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3 years ago

What is the empirical formula of C6H18O3? CH3O C2H5O C2H6O C2H5O5

Chemistry

2 answers:

denis-greek [22]3 years ago

6 0

What is the empirical formula of C6H18O3?

CH3O

C2H5O

C2H6O CORRECT ANSWER

C2H5O5

I took the test and C) was correct

andreyandreev [35.5K]3 years ago

3 0

So to find the empirical formula you have to simplify. What is something you can take out of all three? The number three, so divide everything by three leaving you with (C2H6O). I hope this helped!

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Which of the following shows the conservation of mass during cellular respiration? 3 CO2 3 H2O energy → 3 C6H12O6 3 O2 6 CO2 6 H

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The reaction that has been, following the law of conservation of mass has been $\rm C_6H_1_2O_6\;+\;6\;O_2\;\rightarrow\;6\;CO_2\;+\;6\;H_2O\;+\;Energy$ .

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The law of conservation has been evident when there has been an equal number of atoms of each element on the product and the reactant side.

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The following reactions have been identified as:

$\rm 3\;CO_2\;+\;3\;H_2O\;+\;Energy\;\rightarrow\;3\;C_6H_1_2O_6$

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Reactant = 3

Product = 18

Oxygen atoms

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Hydrogen atoms

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The number of atoms is not equal on the product and reactant side, thus not follows the law of conservation of mass.

$\rm 3\;O_2\;+\;6\;CO_2\;+\;6\;H_2O\;+\;Energy\;\rightarrow\;C_6H_1_2O_6\;+\;6\;O_2$

Carbon atoms

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Oxygen atoms

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Hydrogen atoms

Reactant = 12

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The number of atoms is not equal on the product and reactant side, thus not follows the law of conservation of mass.

$\rm C_6H_1_2O_6\;+\;6\;O_2\;\rightarrow\;6\;CO_2\;+\;6\;H_2O\;+\;Energy$

Carbon atoms

Reactant = 6

Product = 6

Oxygen atoms

Reactant = 18

Product = 18

Hydrogen atoms

Reactant = 12

Product = 12

The number of atoms is equal on the product and reactant side, thus follows the law of conservation of mass.

$\rm 6\;H_2O\;+\;C_6H_1_2O_6\;\rightarrow\;6\;O_2\;+\;Energy$

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Oxygen atoms

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Product = 12

Hydrogen atoms

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Thus, the reaction that has been following the law of conservation of mass has been $\rm C_6H_1_2O_6\;+\;6\;O_2\;\rightarrow\;6\;CO_2\;+\;6\;H_2O\;+\;Energy$ .

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