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GaryK [48]
3 years ago
5

How will the speed of a sound wave change if the temperature of the medium rises?. . Select one of the options below as your ans

wer:. A.. The speed will increase.. B.. The speed will decrease.. . C.. The speed will not change.. . D.. The speed will initially increase and then return to its earlier value.
Physics
2 answers:
Stolb23 [73]3 years ago
5 0
The correct answer for this question is " A.. The speed will i<span>ncrease." The higher the temperature, the more energy it has, and making it to vibrate faster. Since it vibrates faster, then sound waves can travel at a higher speed. In other words, it will make the the speed to increase.</span>
Alex_Xolod [135]3 years ago
3 0
The speed will increase and this is the way the speed of a sound wave changes if the temperature of the medium rises. The correct option among all the options that are given in the question is the first option or option "A". I hope that this answer has come to your help.
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Charra [1.4K]

Answer:

try finding on a website

Explanation:

6 0
3 years ago
A charged particle having mass 6.64 x 10-27 kg (that of a helium atom) moving at 8.70 x 105 m/s perpendicular to a 1.30-T magnet
Fiesta28 [93]

Answer:

the charge of the particle is 2.47 x 10⁻¹⁹ C

Explanation:

Given;

mass of the particle, m = 6.64 x 10⁻²⁷ kg

velocity of the particle, v = 8.7 x 10⁵ m/s

strength of the magnetic field, B = 1.3 T

radius of the circle, r = 18 mm = 1.8 x 10⁻³ m

The magnetic force experienced by the charge is calculated as;

F = ma = qvB

where;

q is the charge of the particle

a is the acceleration of the charge in the circular path

a = \frac{v^2}{r} \\\\ma = qvB\\\\q = \frac{ma}{vB} \\\\q = \frac{mv^2}{rvB} = \frac{mv}{rB} \\\\q = \frac{(6.64\times 10^{-27} ) \times (8.7\times 10^5)}{(1.8\times 10^{-2}) \times (1.3)} \\\\q = 2.47 \ \times 10^{-19} \ C

Therefore, the charge of the particle is 2.47 x 10⁻¹⁹ C

6 0
3 years ago
When you have a pot of water on the stove, heat is transferred to the water. Describe the behavior of the water molecules and ho
Digiron [165]

The hotter molecules become, the faster they move around. The colder they are, the more slow and lethargic they are

3 0
3 years ago
A tangent line drawn on a velocity-time graph has a rise of 19 m/s and a run of 4.0 m/s. How large is the acceleration? What typ
klemol [59]

Answer:

Acceleration = 4.8 m/s²

Explanation:

Given:

Change in velocity = 19 m/s

Change in time = 4 s

Find:

Acceleration

Computation:

Acceleration = Change in velocity / Change in time

Acceleration = 19/4

Acceleration = 4.8 m/s²

Positive acceleration

8 0
3 years ago
Suppose you illuminate two thin slits by monochromatic coherent light in air and find that they produce their first interference
strojnjashka [21]

Answer:

1.7323

Explanation:

To develop this problem, it is necessary to apply the concepts related to refractive indices and Snell's law.

From the data given we have to:

n_{air}=1

\theta_{liquid} = 19.38\°

\theta_{air}35.09\°

Where n means the index of refraction.

We need to calculate the index of refraction of the liquid, then applying Snell's law we have:

n_1sin\theta_1 = n_2sin\theta_2

n_{air}sin\theta_{air} = n_{liquid}sin\theta_{liquid}

n_{liquid} = \frac{n_{air}sin\theta_{air}}{sin\theta_{liquid}}

Replacing the values we have:

n_{liquid}=\frac{(1)sin(35.09)}{sin(19.38)}

n_liquid = 1.7323

Therefore the refractive index for the liquid is 1.7323

6 0
4 years ago
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