The mass of nitrogen collected is mathematically given as
M-N2=0.025gram
<h3>What is the mass of nitrogen collected?</h3>
Question Parameters:
A sample weighing 2.000g
the liberated NH3 is caught in 50ml pipeful of H2SO4 (1.000ml = 0.01860g Na2O).
T=26.3c=299.3K
Pressure=745mmHg=745torr
Pressure of N2=745-25.2=719.8torr
Generally, the equation for the ideal gas is mathematically given as
PV=nRT
Therefore
719.8/760=45.6/1000=n*0.0821*299.3
n=0.00176*14
In conclusion, the Mass of N2
M-N2=0.00176*14
M-N2=0.025gram
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Answer:
Explanation:
Introducción. Dentro de la introducción, el investigador limita el estudio. Muestra los datos generales importantes y...
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Answer:

Explanation:
Volume of a cone:
We have
and we want to find
when the height is 2 cm.
We can see in our equation for the volume of a cone that we have three variables: V, r, and h.
Since we only have dV/dt and dh/dt, we can rewrite the equation in terms of h only.
We are given that the height of the cone is 1/5 the radius at any given time, 1/5r, so we can write this as r = 5h.
Plug this value for r into the volume formula:
Differentiate this equation with respect to time t.
Plug known values into the equation and solve for dh/dt.
Divide both sides by 100π to solve for dh/dt.
The height of the cone is increasing at a rate of 1/10π cm per second.
For the molarity and the percentage of the mass of kcl are mathematically given as
%m/m = 23.1%, molarity = 3.38M
<h3>What is the molarity?</h3>
Generally, the equation for the percentage of the mass of kcl is mathematically given as
(mass of kcl/mass of solution)x 100
therefore
%m/m = (6.31/27.29)x100
%m/m = 23.1%
The molarity
(no of mol/ vol of sol)
molarity = 0.0846mol/0.0250 L
molarity = 3.38M
In conclusion, the molarity is given as
molarity = 3.38M
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Answer:
The liquid level will rise in Side A and drop in Side B.
Step-by-step explanation:
The membrane is impermeable to sucrose, but permeable to sucrose and water.
<u> Side A </u> <u> Side B </u>
2 M sucrose 1 M sucrose
1 M glucose 2 M glucose
(a) Ignoring osmotic effects
The glucose will diffuse spontaneously from the side with higher concentration to that of lower concentration until equilibrium is established. There is no change in volume on either side.
At this point, we have
<u> Side A </u> <u> Side B </u>
2 M sucrose 1 M sucrose
1.5 M glucose 1.5 M glucose
=====
(b) With osmotic effects
The solute concentration on Side A is greater than on Side B.
Water will diffuse into Side A.
The liquid level will rise in Side A and drop in Side B.