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dolphi86 [110]
3 years ago
7

What is the oxidation state of each individual carbon atom in c2o42−?

Chemistry
2 answers:
MA_775_DIABLO [31]3 years ago
7 0

Answer:

+3

Explanation:

The oxygen all have a -2 oxidation state. (peroxides are exceptions)

The chemical structure is symmetrical. Both carbon are equivalent.

2 (oxidation state of carbon) + 4 (oxidation state of oxygen) = charge of ion.

2 (oxidation state of carbon) + 4 (-2) = -2

oxidation state of carbon = +3

nika2105 [10]3 years ago
3 0

Answer:

+3

Explanation:

Hello,

In this case, by knowing that the molecule has the following oxidation states structure, one can solve for the carbon's oxidation state via the total ion's charge as shown below:

(C_2^xO_4^{-2})^{2-}\\2x-8=-2\\x=\frac{-2+8}{2}=+3

Therefore, the carbon's oxidation state is +3

Best regards.

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Colt1911 [192]
It changes the rate of growth that cells usually undergo.
6 0
3 years ago
26.6 mL of 2.50 M stock solution of sucrose is diluted to 50.0 mL. A 16.0 mL sample of the resulting solution is then diluted to
frozen [14]

Answer:

In the final solution, the concentration of sucrose is 0.126 M

Explanation:

Hi there!

The number of moles of solute in the volume taken from the more concentrated solution will be equal to the number of moles of solute in the diluted solution. Then, the concentration of the first solution can be calculated using the following equation:

Ci · Vi = Cf · Vf

Where:

Ci = concentration of the original solution

Vi = volume of the solution taken to prepare the more diluted solution.

Cf = concentration of the more diluted solution.

Vf = volume of the more diluted solution.

For the first dillution:

26.6 ml · 2.50 M = 50.0 ml · Cf

Cf = 26.6 ml · 2.50 M / 50.0 ml

Cf = 1.33 M

For the second dilution:

16.0 ml · 1.33 M = 45.0 ml · Cf

Cf = 16.0 ml · 1.33 M / 45.0 ml

Cf = 0.473 M

For the third dilution:

20.0 ml · 0.473 M = 75.0 ml · Cf

Cf = 20.0 ml · 0.473 M / 75.0 ml

Cf = 0.126 M

In the final solution, the concentration of sucrose is 0.126 M

7 0
3 years ago
Two litres of an ideal gas at a pressure of 10 atm expands isothermally into a vacuum until its total volume is 10 litres. How m
nlexa [21]

Answer:

The work done and heat absorbed are both -8,1 kJ

Explanation:

The work done in an isobaric process is defined as:

W = -P (Vf - Vi)

Where P is pressure ( 10 atm)

Vf = 10 L

Vi = 2 L

Thus, <em>W = -80 atm×L ≡ -8,1 kJ</em>

This is the work done in expansion of the gas.  As the gas remains at the same temperature, there is no change in internal energy doing that all work was absorbed as heat.

I hope it helps!

4 0
3 years ago
X2o3 express you answer as a whole number
kobusy [5.1K]
 <span>2.40 - 1.68 =0.72 g of oxigen 
moles = 0.72/16 g/mol=0.045 

moles x = 1.68/ 55.9=0.03 

0.03/0.03 = 1 = x 
0.045 / 0.03 = 1.5 = O 

to get whole numbers multiply by 2 

x2O3 

X2O3 +3 CO = 2 X + 3 CO2</span>
4 0
3 years ago
The product side of a chemical reaction is shown.
Inga [223]

The number that represents the coefficient on the product side of the chemical reaction, -- > 7Ti_2(SO_4)_3 is 7.

<h3>Coefficients of chemical equations</h3>

In equations representing chemical reactions, the coefficient of each reactant or product of a reaction is the number that comes on the left-hand side just before the chemical formula.

The coefficient of each species in a chemical reaction is obtainable when the equation of the reaction is balanced.

For example, in the following equation: 2A + B = 3C + D

The coefficients of A, B, C, and D are 2, 1, 3, and 1 respectively.

Applying this to the product side of a chemical reaction;  -- > 7Ti_2(SO_4)_3

It means that the coefficient of the product is 7.

More on coefficients of chemical equations can be found here: brainly.com/question/28294176

#SPJ1

7 0
1 year ago
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