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3 years ago

Because of its high reactivity which element is normally obtained by the electrolysis

1 answer:

8 0

Lithium has a property of high reactivity and to obtain lithium is through electrolysis of its fused salts. Because lithium is very reactive, it is not found free so electrolysis is use to split it apart to get it. Moreover, Lithium is an alkali metal with single valence electron that is easily given up to form cation, which make it a good conductor of heat and electricity.

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All of the following statements help to explain why water molecules form hydrogen bonds except:________

Natalka [10]

Answer:- Water is an electronegative molecule.

Explanation:

A molecule cannot be electronegative. Rather the atoms in a molecule may be electronegative. This first statement does not account for the hydrogen bonding in water at all because it is incorrect. However, the other statements in the question sheds more light on the nature of hydrogen bonding in water molecule.

8 0

4 years ago

2.303 3-5.05x10-3 1 | - 1 T2298

bekas [8.4K]

Answer:

230,294.9 I think it's fine just try your past or ask teacher help

6 0

3 years ago

(58 g)/ (4L) reduce units to one

zysi [14]

Answer is 14.5 g L⁻¹.

Explanation;

Here, the question says reduce the units as one.

The presented units are g/L. To reduce the units to one, what we can do is take L to the upper side.

This can be done according to the rules of indices;

1 / aˣ = a⁻ˣ

Like that, we can write 1 / L as L⁻¹.

Hence, the reduced unit is g L⁻¹.

But remember to keep a space between when writing two different units.

Actually, this is an unit for density.

8 0

3 years ago

Fumaric acid is an organic compound composed of 41.39% , 3.47% , and the rest oxygen. If 0.288 mol of fumaric acid has a mass of

Gnesinka [82]

Answer:

Molecular formula: C₄H₄O₄

Empirical formula: CHO

Explanation:

Centesimal composition of fumaric acid:

41.39% C

3.47% H

(100% - 41.39% - 3.47%) = 55.14% O

In 100 g of fumaric, we got:

41.39 g of C

3.47 g of H

55.14 g of O

If we take account that we have x mol of fumaric in x mass of the same compound (g/mol), we can determine molar mass.

33.4 g / 0.288 mol → 116 g/mol

Now, we can prepare this rules of three:

In 100 g of fumaric we have 41.39 g of C, 3.47 g of H, 55.14 g of O

Then 116 g of fumaric will have:

(116 . 41.39) / 100 = 48 g C

(116 . 3.47) / 100 = 4 g H

(116. 55.14) / 100 = 64 g O

If we convert the mass to moles, we reach the molecular formula:

48 g . 1mol /12 g = 4 moles C

4 g . 1mol /1g = 4 moles H

64 . 1mol/16 g = 4 moles O

Molecular formula: C₄H₄O₄

Empirical formula: CHO

5 0

4 years ago

Read 2 more answers

Assuming the metals lose all their valence electrons and the nonmetals gain electrons to complete the s-p subshells, which listi

Nataly [62]

Answer: Option (c) is the correct answer.

Explanation:

Atomic number of sodium is 11 and its electronic configuration is $1s^{2}2s^{2}2p^{6}3s^{1}$ . When sodium loses one electron then it will attain +1 charge and its electronic configuration will be as follows.

$Na^{+}$ : $1s^{2}2s^{2}2p^{6}$

Atomic number of fluorine is 9 and its electronic configuration is $1s^{2}2s^{2}2p^{5}$ . When fluorine gains an electron then it acquires -1 charge and its electronic configuration is as follows.

$F^{-}$ : $1s^{2}2s^{2}2p^{6}$

Atomic number of aluminium is 13 and its electronic configuration is $1s^{2}2s^{2}2p^{6}3s^{2}3p^{1}$ . When aluminium loses its valence electrons then it acquires +3 charge and its electronic configuration is as follows.

$Al^{3+}$ : $1s^{2}2s^{2}2p^{6}$

Thus, we can conclude that the listing for aluminum is correct.

8 0

3 years ago