Given:
m = 555 g, the mass of water in the calorimeter
ΔT = 39.5 - 20.5 = 19 °C, temperature change
c = 4.18 J/(°C-g), specific heat of water
Assume that all generated heat goes into heating the water.
Then the energy released is
Q = mcΔT
= (555 g)*(4.18 J/(°C-g)*(19 °C)
= 44,078.1 J
= 44,100 J (approximately)
Answer: 44,100 J
Answer:
5000 kg/m^3
Explanation:
Here. we are asked to calculate the density of the rock specimen.
we proceed as follows;
mass of water displaced is calculated by finding the difference between the actual and apparent masses
This has a value of 0.45kg - 0.36kg = 0.09kg
The rock and water that is displaced have exactly the same volume and thus their densities is the same. This makes the ratio of their masses to be the same
Ratio of masses is
0.45 / 0.09 = 5.0
Here we can see that the mass of the rock is five times the mass of the water so it must be five times denser
Thus, since the density of water is 1000 kg/m^3 , the density of rock is 5000 kg/m^3
Answer:
mass X velocity
Explanation:
The momentum of a body is the product of its mass and velocity
Answer:
<h2>0.432mA</h2>
Explanation:
Current produced by the solar cells of the pocket calculator is expressed using the formula I = Q/t where;
Q is the charge (in Columbs)
t is the time (in seconds)
Given parameters
Q = 4.2C
t = 2.7 hrs
t = 2.7*60*60
t = 9720 seconds
Required
Current produced by the solar cell I
Substituting the given values into the formula;
I = 4.2/9720
I = 0.000432A
I = 0.432mA
Hence, the current in milliamperes produced by the solar cells of a pocket calculator is 0.432mA
Work = (force) x (distance)
Each time she lifts the weight, she does
(550 N) x (0.5 m) = 275 joules of work against gravity.
Each time she lets the bar down gently, gravity does
(550 N) x (0.5 m) = 275 joules of work against her muscles.
If the human physical muscular system were 100% efficient, and capable
of absorbing work as well as spending it, then the bodybuilder would do
exactly zero work in the process of 1-up followed by 1-down.