Ask question

Ask question

All categories

Svetllana [295]

3 years ago

12

Calculate the power rating of a home appliance (in kilowatts) that uses 5.1 amps of current when plugged into a 120 Volt outlet.

Write your answer to the second decimal place.

1 answer:

Mrrafil [7]3 years ago

4 0

Answer:0.612 kilowatts

Explanation:

Current=5.1 amperes

Voltage=120 volts

Power=current x voltage

Power=5.1 x 120

Power=612

power=612 watts

power=612/1000 kilowatts

Power=0.612 kilowatts

You might be interested in

A certain ideal gas has molar heat capacity at constant volume CV. A sample of this gas initially occupies a volume V0 at pressu

ANTONII [103]

Answer:

Explanation:

The processes are described on the image attached below. The isobaric process consists of an horizontal line, the adiabatic expansion is described by a polytropic curve:

$P_{2} \cdot V_{2}^{\gamma} = P_{3} \cdot V_{3}^{\gamma}$

Where:

$\gamma = \frac{c_{p}}{c_{v}}$

$\gamma = 1 + \frac{R}{c_{v}}$

Final pressure is:

$P_{3} = P_{2}\cdot \left(\frac{V_{2}}{V_{3}} \right)^{\gamma}$

$P_{3} = P_{o}\cdot \left(\frac{1}{2}\right)^{\gamma}$

$P_{3} = \frac{P_{o}}{2^{\gamma}}$

8 0

3 years ago

What is the gravitational potential energy of a tiger that weighs 200 N standing on a rock that is 2 m above the ground?

Nikitich [7]

G.P.E = mgh
Weight = mg = 200N

So G.P.E = 200 * 2 = 400 Joules

5 0

3 years ago

A red laser from the physics lab is marked as producing 632.8-nm light. When light from this laser falls on two closely spaced s

Hatshy [7]

Answer:

Explanation:

fringe separation or fringe width is directly proportional to wavelength .

Δ₁ / Δ₂ = wave length of first laser / wavelength of second laser

Δ₁ is fringe separation in first case and Δ₂ is fringe separation in second case.

putting the given values

632.8 / wavelength of second laser = 4.5 / 4.64

wavelength of second laser = 632.8 x (4.64 / 4.5)

= 652.48 nm

652 nm

3 0

3 years ago

4. What is the electric field strength 1.4 nm from a charge of 4.7 cC?

pentagon [3]

The electric field strength is $2.16\cdot 10^{26} N/C$

Explanation:

The strength of the electric field produced by a single point charge is given by:

$E=k\frac{q}{r^2}$

where

$k=8.99\cdot 10^9 Nm^{-2}C^{-2}$ is the Coulomb's constant

q is the magnitude of the charge

r is the distance from the charge at which the field strength is calculated

For the charge in the problem, we have:

$q=4.7 cC = 0.047 C$ is the charge

$r=1.4 nm = 1.4\cdot 10^{-9} m$

Therefore, the electric field strength is

$E=(8.99\cdot 10^9)\frac{0.047}{(1.4\cdot 10^{-9})^2}=2.16\cdot 10^{26} N/C$

Learn more about electric fields:

brainly.com/question/8960054

brainly.com/question/4273177

#LearnwithBrainly

5 0

3 years ago

List the metric base units for the following:

77julia77 [94]

Meter
meter
gram
Celsius

4 0

3 years ago

Read 2 more answers