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Svetllana [295]

3 years ago

12

Calculate the power rating of a home appliance (in kilowatts) that uses 5.1 amps of current when plugged into a 120 Volt outlet.

Write your answer to the second decimal place.

1 answer:

Mrrafil [7]3 years ago

4 0

Answer:0.612 kilowatts

Explanation:

Current=5.1 amperes

Voltage=120 volts

Power=current x voltage

Power=5.1 x 120

Power=612

power=612 watts

power=612/1000 kilowatts

Power=0.612 kilowatts

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How many layers does the world have?

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Which of the following is the center of the universe according to the geocentric model?

Dima020 [189]

Earth is the center according to the geocentric model.

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a 1500.0 kg car is at rest on a level track. The driver gives the engine gas and the car begins to accelerate forward. The car m

padilas [110]

Acceleration of the car is 3.375 m/s² and the force of the car moving forward is 5062.5 N

Explanation:

Acceleration is the rate of change of velocity.
It is given by the equation, a = change in velocity/time

Here, velocity changes from 0 to 27 m/s and time = 8

⇒ Acceleration = 27 - 0/8 = 27/8 = 3.375 m/s²

Force is calculated by the equation, F = Mass × Acceleration
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4 0

3 years ago

BRAINLIEST WILL BE MARKED FOR THE FIRST ANSWER

slamgirl [31]

Answer:

The weight of the body in the new planet is 100 newtons.

Explanation:

From Newton's Law of Gravitation we find that gravitational force is directly proportional to mass of the planet and inversely proportional to the square of its radius. From this fact we can build the following relationship:

$\frac{F_{1}\cdot R_{1}^{2}}{M_{1}} = \frac{F_{2}\cdot R_{2}^{2}}{M_{2}}$ (1)

Where:

$F_{1}$ , $F_{2}$ - Gravitational force, measured in newtons.

$M_{1}$ , $M_{2}$ - Mass of planet, measured in kilograms.

$R_{1}$ , $R_{2}$ - Radius of the planet, measured in meters.

If we know that $F_{1} = 800\,N$ , $\frac{M_{2}}{M_{1}} = \frac{1}{2}$ and $\frac{R_{2}}{R_{1}} = 2$ , then the expected gravitational force in the new planet is:

$F_{2} = F_{1}\cdot \left(\frac{M_{2}}{M_{1}} \right)\cdot \left(\frac{R_{1}} {R_{2}}\right)^{2}$

$F_{2} = (800\,N)\cdot \left(\frac{1}{2} \right)\cdot \left(\frac{1}{2}\right)^{2}$

$F_{2} = 100\,N$

The weight of the body in the new planet is 100 newtons.

4 0

3 years ago