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svlad2 [7]
3 years ago
15

What is the charge on an electron? –1 0 +1 +2

Chemistry
2 answers:
Maksim231197 [3]3 years ago
8 0

Answer:

The charge of an electron is -1

Explanation:

The electron is a subatomic particle located in orbitals of atoms. The subatomic particle that has a charge equal to +1 is the proton and the neutron has a charge equal to zero. Protons and neutrons are located in the nucleus of the atom.

Maurinko [17]3 years ago
7 0

Answer: -1

Explanation:

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How many moles of KCIO3 are required to produce 58.3 grams of 02? <br> 2 KCIO3 —&gt; 2 KCI + 3 O2
strojnjashka [21]

Answer:

1.21 mol KClO₃

General Formulas and Concepts:

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Moles
  • Mole Ratio

<u>Stoichiometry</u>

  • Analyzing reactions rxn
  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

<em>Identify variables</em>

[rxn] 2KClO₃ → 2KCl + 3O₂

[Given] 58.3 g O₂

[Solve] mol KClO₃

<u>Step 2: Identify Conversions</u>

[rxn] 2 mol KClO₃ → 3 mol O₂

[PT] Molar Mass of O: 16.00 g/mol

Molar Mass of O₂: 2(16.00) = 32.00 g/mol

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                       \displaystyle 58.3 \ g \ O_2(\frac{1 \ mol \ O_2}{32.00 \ g \ O_2})(\frac{2 \ mol \ KClO_3}{3 \ mol \ O_2})
  2. [DA] Divide/Multiply [Cancel out units]:                                                           \displaystyle 1.21458 \ mol \ KClO_3

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

1.21458 mol KClO₃ ≈ 1.21 mol KClO₃

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3 years ago
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5 0
4 years ago
Calculate the empirical formula of a compound that has a composition of 5.9% (by mass) hydrogen and 94.1% (by mass) oxygen.​
adelina 88 [10]

Answer:

The empirical formula is the simplest form;

Given:

Oxygen O at 94.1% and

H at 5.9%

Assume 100grams.

94% = 0.941 x 100gm. = 94.1 gm x 1mole/16gm. = 5.88 moles of O

5.9% = 0.059 x 100gm. = 5.9gm. X 1moleH/1.002gm. = 5.88 moles of H

There is one mole of O for each mole of H so the empirical formula is O_1H_1

and written as OH.

8 0
3 years ago
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katrin2010 [14]

Answer: Each ion, or atom, has a particular mass; similarly, each mole of a given pure substance also has a definite mass. The mass of one mole of atoms of a pure element in grams is equivalent to the atomic mass of that element in atomic mass units (amu) or in grams per mole (g/mol).

Explanation:

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3 years ago
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