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In-s [12.5K]
2 years ago
8

Describe the process of melting of ice in terms of particles present​

Chemistry
2 answers:
marta [7]2 years ago
5 0

Answer:

<em>The solid ice particles absorb heat energy from the warmer air, giving the particles energy and enabling them to move away from one another.</em>

OverLord2011 [107]2 years ago
4 0

Explanation:

Solid to liquid particles

Melting of ice goes through two stages, solid and liquid

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Compound Y has a distribution coefficient of 4.0 when extracted from water with chloroform, with Y being more soluble in chlorof
Aleks04 [339]

Answer:

There are needed 3 extractions to extract at least 95%

Explanation:

The distribution coefficient of a compound is defined as the ratio in concentration of the compound in the organic solvent and the concentration in the aqueous solution:

K = Concentration organic solvent / Concentration in water

Assuming as initial amount of the organic solvent: 100% and X as the amount of Y that is extracted

<em>First extraction:</em>

4 = X / 10mL / (100-X) / 50mL

4 = 50X / 1000-X

4000 - 4X = 50X

4000 = 54X

X = 74.1%

In the first extraction, 74.1% of Y is extracted

And will remain: 100 - 74.1 = 25.9%

<em>Second extraction:</em>

4 = X / 10mL / (25.9-X) / 50mL

4 = 50X / 259-X

1036 - 4X = 50X

1036 = 54X

X = 19.2%

In the second extraction, 19.2% of Y is extracted

And will remain: 25.9 - 19.2 = 6.7%

<em>Third extraction</em>

4 = X / 10mL / (6.7-X) / 50mL

4 = 50X / 67-X

268 - 4X = 50X

268 = 54X

X = 5.0%

In the first extraction, 5.0% of Y is extracted

And are extracted:

74.1% + 19.2% + 5.0% = 98.3%

That means there are needed 3 extractions to extract at least 95%

4 0
2 years ago
Write a balanced chemical equation describing the oxidation of the bromide ion by solid xenon trioxide to produce bromine liquid
ki77a [65]

Answer:

6Br⁻ + XeO₃ + 6H⁺ → 3Br₂ + Xe + 3H₂O  

Explanation:

First, we need to write the half-reactions:

2Br⁻ → Br₂ + 2e⁻ Oxidation -Balanced yet-

XeO₃ →  Xe Reduction

To balance the reduction in acidic aqueous solution we need to add waters in the other side of the reaction as oxygens are present:

XeO₃ →  Xe + 3H₂O

And H⁺ as hydrogens from water we have:

XeO₃ + 6H⁺ →  Xe + 3H₂O

To balance the charge:

<h3>XeO₃ + 6H⁺ + 6e⁻ →  Xe + 3H₂O  Reduction -Balanced-</h3><h3 />

To cancel out the electrons of both half-reaction we need to multiply oxidation 3 times:

6Br⁻ → 3Br₂ + 6e⁻

XeO₃ + 6H⁺ + 6e⁻ →  Xe + 3H₂O  

And the balanced reaction in acidic aqueous solution is the sum of both half-reactions:

<h3>6Br⁻ + XeO₃ + 6H⁺ → 3Br₂ + Xe + 3H₂O  </h3>
5 0
2 years ago
Other than bacteria, which factor leads to nitrogen fixation?
alina1380 [7]
Lightning rain can lead to nitrogen fixation other than bacteria
4 0
3 years ago
Read 2 more answers
Helppppp pls it’s due by today
Andrews [41]

Answer:

i can't see the picture

Explanation:

4 0
3 years ago
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How many moles of nitrogen are contained in 18.65 L at STP?
stira [4]
1 mole of any gas under STP  ----- 22.4 L

18.65 L*1 mol/22.4 L ≈ 0.8326 mol N2
8 0
3 years ago
Read 2 more answers
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