Answer:
713.51 N/m
Explanation:
Hook's Law: This law states that provided the elastic limit is not exceeded, the extension in an elastic material is directly proportional to the applied force.
From hook's law,
F = ke ...........................Equation 1
Where F = Force exerted on the bowstring, e = Extension/compression of the bowstring, k = Spring constant of the bow.
Make k the subject of the equation,
k = F/e ............................ Equation 2
Given: F = 264 N, e = 0.37 m.
Substitute into equation 2
k = 264/0.37
k = 713.51 N/m
Hence the spring constant of the bow = 713.51 N/m
Answer: The solution will remain yellow.
Explanation:
Molar mass:
Ag = 107.86 g/mol
Cu = 63.54 g/mol
Mole ratio:
Cu(s)+2 AgNO₃(aq)→Cu(NO₃)₂(aq)+2 Ag(s)
63.54 g Cu ------------- 2 x 107.86 g Ag
1.50 g Cu -------------- ??
Mass Ag = 1.50 x 2 x 107.86 / 63.54
Mass Ag = 32358 / 63.54
= 509.25 g of Ag
hope this helps!
Answer:
E)SOCl2
Explanation:
The best reagents used in the conversion of methyl alcohol to methylchloride is SOCl2. This is because during the conversion the Chloride reacts with the methyl alcohol.
