<h3>
Answer:</h3>
0.0157 g Au
<h3>
General Formulas and Concepts:</h3>
<u>Chemistry</u>
<u>Atomic Structure</u>
- Reading a Periodic Table
- Using Dimensional Analysis
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
3.113 g Au
<u>Step 2: Identify Conversions</u>
Molar Mass of Au - 197.87 g/mol
<u>Step 3: Convert</u>
<u />
= 0.015733 g Au
<u>Step 4: Check</u>
<em>We are given 3 sig figs. Follow sig fig rules and round.</em>
0.015733 g Au ≈ 0.0157 g Au
Answer:
3.75 L
Explanation:
We can solve this problem by using <em>Charles' law</em>, which states:
Where subscript 1 stands for initial volume and temperature and subscript 2 for final volume and temperature, meaning that in this case:
We <u>input the data</u>:
- 2.5 L * 300 K = V₂ * 200 K
And <u>solve for V₂</u>:
It’s is a!!!!! Also can I Have Brainlyest please :)