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Dennis_Churaev [7]
3 years ago
8

Select all that apply.

Physics
2 answers:
Jobisdone [24]3 years ago
6 0
\text{Acceleration}=\frac{d^2}{dt^2}\text{displacement}
So the dimensions of acceleration is LT^{-2}
Any answer that comes under that definition is correct.
spin [16.1K]3 years ago
6 0
Strange as it may seem, four of those five choices 
are perfectly good units of acceleration.

The only one that isn't is the one in the middle:  ft/s
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neptune is an average distance of 4.5×10^12m from the sun. Estimate the length of the Neptunian year.
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As per Kepler's third law we know that

\frac{T_1^2}{T_2^2} = \frac{R_1^3}{R_2^3}

now here we know that

T_1 = year of Neptune

T_2 = year of Earth

R_1 = distance of Neptune from Sun

R_2 = Distance of Earth from Sun

so now we will have

\frac{T_1^2}{1} = \frac{(4.5 \times 10^{12})^3}{(1.5 \times 10^11)^3}

T_1^2 = 27000

T_1 = 164.3 years

so length of year of Neptune is 164.3 years

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