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3 years ago

Select all that apply.

2 answers:

6 0

$\text{Acceleration}=\frac{d^2}{dt^2}\text{displacement}$
So the dimensions of acceleration is $LT^{-2}$
Any answer that comes under that definition is correct.

spin [16.1K]3 years ago

6 0

Strange as it may seem, four of those five choices
are perfectly good units of acceleration.

The only one that isn't is the one in the middle: ft/s

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What kind of change is it when a liquid turns into a gas by boiling????????????????????

elixir [45]

It is called vaporization. Vaporization is the phase transition from a liquid to a gas by means of evaporation or boiling. Evaporation occurs at temps below the boiling point and occurs on the liquids surface. Boiling is a rapid vaporization that occurs above the boiling temp and below or at the liquids surface.

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3 years ago

Compared with the amount of current in the filament of a lamp, the amount of current in the connecting wire is A. definitely les

pashok25 [27]

Compared with the amount of current in the filament of a lamp, the amount of current in the connecting wire is

D. the same.

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3 years ago

Read 2 more answers

Mr. Beall paddles his canoe at 8.0 m/s North in a river that flows at 6.0 m/s to the South. What is the magnitude and direction

kifflom [539]

Answer:

2 /s north

Explanation:

Given that,

Velocity due North is 8 m/s and due south is 6 m/s

We need to find the magnitude and the direction of the resulting velocity.

Let North is positive and South is negative. When two velocities are in opposite direction, they adds up. So,

$v=8+(-6)\\\\v=2\ m/s$

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2 years ago

Consider as a system the Sun with Saturn in a circular orbit around it. Find the magnitude of the change in the velocity of the

Doss [256]

Answer:

$v_{su} = 19.44 m/s$

Explanation:

$m_{su}=5.68x10^{29}kg\\m_{sa}=5.68x10^{26}kg$

$T=9.29x10^8\\r_{o}=1.43x10^{12}$

If the sun considered as x=0 on the axis to put the center of the mass as a:

$m_{su}*r_{o}=(m_{sa}+m_{su})*r_{1}$

solve to r1

$r_1=\frac{m_{sa}*r_{o}}{m_{sa}+m_{su}}=\frac{5.68x10^{26}*1.43x10^{12}}{5.68x10^{26}+5.68x10^{26}}$

$r_1=1.428x10^9m$

Now convert to coordinates centered on the center of mass. call the new coordinates x' and y' (we won't need y'). Now since in the sun centered coordinates the angular momentum was

$L = \frac{m_{sa}*2*pi*r_1^2}{T}$