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lakkis [162]
3 years ago
9

Please HELP ME If the motion of an object changes, what must be true about the forces acting on that object?

Physics
2 answers:
Leokris [45]3 years ago
5 0

Answer: Unbalanced forces cause an object to start moving, stop moving, or change direction. Unbalanced forces acting on an object will change the object's motion. Unbalanced forces can also stop a moving object.

Explanation:

atroni [7]3 years ago
4 0

Answer:

If there is a net force acting on an object, the object will have an acceleration and the object's velocity will change. ... Newton's second law states that for a particular force, the acceleration of an object is proportional to the net force and inversely proportional to the mass of the object.

Explanation:

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How do the nonliving parts of earth's systems provide the basic materials to support life?
MatroZZZ [7]
The abiotic community of the ecosystem or the nonliving objects in the earth's biosphere influences the survival, growth and development of the organism. They provide basic mmaterials to support life by the biogeochemical processes which is composed of many biological and environmental cycles which profoundly has factored the intiation and continuation of life on earth. They also provide the basic materials to support life by the undergoing process which is also initiated by the living creatures or the biotic society of the ecosystem.
3 0
3 years ago
A 3.00-kg object has a velocity 16.00 i ^ 2 2.00 j ^2 m/s.
trapecia [35]

Answer:

390 J

Explanation:

m = 3 kg

u = 16 i + 2 j

(a) Magnitude of velocity = \sqrt{16^{2}+2^{2}} = 16.1245 m/s

KEi = 1/2 m v^2 = 0.5 x 3 x 16.1245 = 390 J

(b) v = 18 i + 14 j

Magnitude of velocity =  \sqrt{18^{2}+14^{2}} = 22.804 m/s

KEf = 1/2 m v^2 = 0.5 x 3 x 22.804 = 780 J

According to the work energy theorem

Work done = change in KE = KEf - KEi = 780 - 390 = 390 J

8 0
4 years ago
A runner achieves a velocity of 11.1 m/s, 9 sec after he begins. What is his
Elena-2011 [213]

Answer:

1.23 m/s²

Explanation:

Given:

v₀ = 0 m/s

v = 11.1 m/s

t = 9 s

Find: a

Equation:

v = at + v₀

Plug in:

11.1 m/s = a (9 s) + 0 m/s

a = 1.23 m/s²

The runner's acceleration is 1.23 m/s².

7 0
3 years ago
Please help on this one
mixas84 [53]
Ep=mgh
h= Ep/mg
h=57÷(3.3×9.8)
h= 57÷32.34
h= 1.8m
So; the answer is B. 1.8m
6 0
3 years ago
An air compressor and takes atmospheric Air at 14.7 PSI and increases its pressure to 150 psi ( Gauge). the pressurized air is s
Yuliya22 [10]

Answer:

The absolute pressure of air inside the tank is 164.7 psi.

Explanation:

Given that,

Atmospheric pressure = 14.7 Psi

Gauge pressure = 150 psi

We need to calculate the absolute pressure of air inside the tank

Using formula of absolute pressure

P_{ab}=P_{g}+P_{atm}

Where, P_{g} = gauge pressure

P_{atm} =atmospheric pressure

Put the value into the formula

P_{ab}=150+14.7

P_{ab}=164.7\ psi

Hence, The absolute pressure of air inside the tank is 164.7 psi.

3 0
3 years ago
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