3 years ago

Two waves, each with intensity 40 db, interfere constructively. what is the intensity of the combined waves, in db?

Physics

1 answer:

Nikitich [7]3 years ago

4 0

I'm not really sure it's been awhile since I did this.

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If a vector that is 3cm long represents 30 km/h, what velocity does a 5 cm long vector which is drawn using the same scale repre

poizon [28]

Answer: A. 50 km/h

Explanation:

3 * 10 = 30

5 * 10 = 50

5 0

2 years ago

Two streams merge to form a river. One stream has a width of 8.9 m, depth of 3.8 m, and current speed of 2.3 m/s. The other stre

SpyIntel [72]

<h2>Depth of river is 4.48 m</h2>

Explanation:

Discharge = Area x Velocity

Discharge of river = Discharge of stream 1 + Discharge of stream 2

$A_rv_r=A_1v_1+A_2v_2$

Area of stream 1 = w₁ x d₁ = 8.9 x 3.8 = 33.82 m²

Area of stream 2 = w₂ x d₂ = 6.5 x 3.9 = 25.35 m²

Velocity of stream 1 = 2.3 m/s

Velocity of stream 2 = 2.6 m/s

Velocity of river = 3 m/s

$\texttt{Area of river = }w_r\times d_r=10.7\times d_r$

Substituting

$A_rv_r=A_1v_1+A_2v_2\\\\10.7\times d_r\times 3=33.82\times 2.3+25.35\times 2.6\\\\d_r=4.48m$

Depth of river = 4.48 m

7 0

3 years ago

Find the geometric mean of 7 and 25

lana [24]

Answer:

it's sqrt 175 which is pretty close to 14(sqrt 176)

Explanation:

geo mean is a*b

then square rooted

to get the mean

7 0

3 years ago

Read 2 more answers

A red pool ball is rolling directly east before it collides with the

ikadub [295]

Answer: North East

Explanation: Trust me, I was just doing this on the Ck-12 and this the answer I choose and It said I'm correct.

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2 years ago

16 A 20-pewton force daurected west and a 5 newton force directed north act concurently on a 5 kg object. Draw the resultant vec

atroni [7]

Answer:

20.62 N

4.123 m/s^2

Explanation:

A = 20 N west

B = 5 N North

m = 5 kg

Both the forces acting at right angle

Use the formula of resultant of two vectors.

Let r be the magnitude of resultant of two vectors.

$R = \sqrt{A^{2} + B^{2} + 2 A B Cos\theta}$

$R = \sqrt{20^{2} + 5^{2} + 2 \times 20 \times 5 \times Cos90}$

R = 20.62 N

Let a be the acceleeration.

a = Net force / mass = R / m = 20.62 / 5

a = 4.123 m/s^2

8 0

3 years ago