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Free_Kalibri [48]
3 years ago
13

120 grams of calcium nitrite Ca(NO2)2 is dissolved in a 240 mL solution. What is the molarity of the solution???

Chemistry
1 answer:
expeople1 [14]3 years ago
5 0

Hey there!:

Molar mass Ca(NO2)2 = 132.089 g/mol

Mass of solute = 120 g

Number of moles:

n = mass of solute / molar mass

n = 120 / 132.089

n = 0.0009084 moles of Ca(NO2)2

Volume in liters of solution :

240 mL / 1000 => 0.24 L

Therefore:

Molarity = number of moles / volume of solution

Molarity = 0.0009084 / 0.24

Molarity = 0.003785 M

Hope that helps!

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Draw a Lewis structure for ketene, C2H2O , which has a carbon‑carbon double bond. Include all hydrogen atoms and show all unshar
Vladimir79 [104]

<u>Answer:</u> The lewis dot structure is attached below.

<u>Explanation:</u>

A Lewis dot structure is defined as the representation of atoms having electrons around the atom where electrons are represented as dots.

A ketene is an organic compound having general formula R′R″C=C=O, where R and R' are two different/same monovalent chemical groups.

The given chemical compound having formula C_2H_2O is represented as H_2-C=C=O.

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The lewis dot structure of C_2H_2O is given in the image below.

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3 years ago
A chemical reaction is shown below:
BabaBlast [244]

Answer:

Mass = 8.46 g

Explanation:

Given data:

Mass of water produced = ?

Mass of glucose = 20 g

Mass of oxygen = 15 g

Solution:

Chemical equation:

C₆H₁₂O₆ + 6O₂     →   6H₂O + 6CO₂

Number of moles of glucose:

Number of moles = mass/molar mass

Number of moles = 20 g/ 180.16 g/mol

Number of moles = 0.11 mol

Number of moles of oxygen:

Number of moles = mass/molar mass

Number of moles = 15 g/ 32 g/mol

Number of moles = 0.47 mol

now we will compare the moles of water with oxygen and glucose.

               C₆H₁₂O₆           :            H₂O

                   1                   :              6

                 0.11                :           6/1×0.11 = 0.66

                   O₂               :            H₂O

                   6                   :              6

                 0.47                :           0.47

Less number of moles of water are produced by oxygen thus it will limit the yield of water and act as limiting reactant.

Mass of water produced:

Mass = number of moles × molar mass

Mass = 0.47 mol  ×18 g/mol

Mass = 8.46 g

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