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Assoli18 [71]
2 years ago
15

1. The heat absorbed when ice melts can

Chemistry
1 answer:
zmey [24]2 years ago
3 0
4 a joule is the answer
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When 7.085 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 21.71 grams of CO2 and 10.37 grams of H
Taya2010 [7]

Answer:

- Empirical:

C_3H_7

- Molecular:

C_6H_{14}

Explanation:

Hello,

In this case, based on the information regarding the combustion, the moles of carbon turn out:

n_C=21.71gCO_2*\frac{1molCO_2}{44gCO_2}*\frac{1molC}{1molCO_2}=0.493molC

Moreover, the moles of hydrogen:

n_H=10.37gH_2O*\frac{1molH_2O}{18gH_2O}*\frac{2molH}{1molH_2O}=1.152molH

Thus, the subscripts of carbon and hydrogen in the hydrocarbon turn out:

C=\frac{0.4934}{0.4934}=1\\H=\frac{1.15222}{0.4934}=2.335\\CH_{2.335}

Now, looking for a suitable whole number we obtain the following empirical formula as 2.335 times 3 is 7 for hydrogen:

C_3H_7

In such a way, that compound has a molar mass of 43 g/mol, thus, the whole compound's molar mass is 86.18 g/mol for which the molecular formula is twice the empirical one, therefore:

C_6H_{14}

Which is hexane.

Best regards.

6 0
3 years ago
According to the collision theory and model created to explain the collision theory, what two factors must be satisfied for a gi
storchak [24]
The answer is correct orientation and sufficient energy. Answer choice D
4 0
2 years ago
Read 2 more answers
PLEASE HELP!!!!!!! CHEMISTRY!!!!
AnnZ [28]

Answer:

dude im sorry for your loss best of luck to you and your answer search

Explanation:

3 0
3 years ago
What is the change of state from solid to liquid called?
Sophie [7]
It is melting point process
4 0
3 years ago
What mass percent solution will result from dissolving 0.126 moles of AgNO3 in 475 g. of water
Kruka [31]

Answer:

The answer to your question is: 4.5 %

Explanation:

0.126 moles of AgNO3

mass percent = ?

mass of water = 475 g

Formula

               weight percent = weight of solute / weight of solution x 100

Weight of solute

 MW AgNO3 = 108 + 14 + (16 x 3)

                      = 108 + 14 + 48

                     = 170 g

                        170 g of AgNO3 -------------------  1 mol

                        x                         ---------------------  0.126 moles

                        x = (0.126 x 170) / 1  = 21.42 g of AgNO3

Weight percent = 21.42/475 x 100

                          = 4.5 %

7 0
3 years ago
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