Answer:
1429.32 mmHg
Explanation:
Initial Pressure P1 = 3000.0mmHg
Initial Temperature T1 = 500.0°C + 273 = 573 K ( Converting to kelvin temperature)
Final Temperature T2 = 0.00°C + 273 = 273 K ( Converting to kelvin temperature)
Final Pressure P2 = ?
The pressure of a given amount of gas is directly proportional to the absolute temperature provided volume remains constant.
This is given by the mathematical expression;
P1 / T1 = P2 / T2
Inserting the values;
3000 / 573 = P2 / 273
P2 = 273 * 3000 / 573
P2 = 1429.32 mmHg
Answer: That is, the suffix of the compound is unchanged by the presence of the halogen, and the halogen is included as a prefix in the name. In acyl halides, the suffix -oyl chloride is appended to the name. For example, CH3CH2COCl is called propanoyl chloride.
Explanation:
Pretty sure its all of the above since all of them are true
Answer:
Percent Yield Fe = 82.5%
Explanation:
The actual yield is the value produced after an experiment is conducted. The theoretical yield is the value calculated using the balanced chemical equation and atomic/molar masses.
To find the percent yield of iron (Fe), you need to (1) convert grams Al to moles Al (via atomic mass), then (2) convert moles Al to moles Fe (via mole-to-mole ratio from equation coefficients), then (3) convert moles Fe to grams Fe (via atomic mass), and then (4) calculate the percent yield. It is important to arrange the ratios in a way that allows for the cancellation of units. The final answer should have 3 sig figs to reflect the sig figs of the given values.
Atomic Mass (Mg): 24.305 g/mol
Atomic Mass (Fe): 55.845 g/mol
3 Mg + 2 FeCl₃ -----> 2 Fe + 3 MgCl₂
20.5 g Mg 1 mole 2 moles Fe 55.845 g
----------------- x ----------------- x ---------------------- x ----------------- =
24.305 g 3 moles Mg 1 mole
= 31.4 g Fe
Actual Yield
Percent Yield = ---------------------------------- x 100%
Theoretical Yield
25.9 g Fe
Percent Yield = -------------------- x 100%
31.4 g Fe
Percent Yield = 82.5%
Hey, lovely! It's a pretty lengthy process but here is a pretty clear video on how to do it. Hope this helps ya!
https://www.khanacademy.org/science/chemistry/chemical-reactions-stoichiome/balancing-chemical-equat...
