Answer: 33.35 minutes
Explanation:
A(t) = A(o) *(.5)^[t/(t1/2)]....equ1
Where
A(t) = geiger count after time t = 100
A(o) = initial geiger count = 400
(t1/2) = the half life of decay
t = time between geiger count = 66.7 minutes
Sub into equ 1
100=400(.5)^[66.7/(t1/2)
Equ becomes
.25= (.5)^[66.7/(t1/2)]
Take log of both sides
Log 0.25 = [66.7/(t1/2)] * log 0.5
66.7/(t1/2) = 2
(t1/2) = (66.7/2 ) = 33.35 minutes
Answer:
full load current = 7.891151 A
so correct option is b. Ir= 7.89
Explanation:
given data
Energy E = V = 240 V
frequency = 60 Hz
full-load slip = 0.02
full-load speed = 1764 rpm
winding resistance = 0.6 Ω
winding reactance = 5 Ω
to find out
rotor current at full-load
solution
we will apply here full load current formula that is express as
full load current =
...................1
here S is full-load slip and E is energy given and R is winding resistance and X is winding reactance
put here value we get
full load current =
full load current = 7.891151 A
so correct option is b. Ir= 7.89
Answer:
the work done by the linear spring will be equal to 23.04 k J
Explanation:
given,
k = 32 k N /m
deflected spring = 120 cm
= 1.2 m
work done by spring can be calculate as
= 
= 
= 23.04 k J
hence, the work done by the linear spring will be equal to 23.04 k J
Answer:
Check the explanation
Explanation:
Kindly check the attached image below to see the step by step explanation to the question above.
Answer:
$958.25
Explanation:
PV = FV(1 +r)^(-t) . . . . present value of an amount earning rate r compounded annually for t years
PV = $3000(1.08^-5) ≈ $2041.75
The equivalent present value is $2041.75.
__
This amount is less than the offered amount by ...
$3000 -2041.75 = $958.25
She should pay you $958.25 less in order to make the offers equivalent.