Explanation:
It is necessary that the student is always focused on his / her greatest goal in his / her academic life. There are many students who aspire to enter a certain college, or to pursue a particular professional career. So my advice for facing social changes that can have a negative impact on your success as a student is to plan your future goals and ambitions, always be up to date with the demands of society, seek help if necessary and always dedicate yourself to the maximum in your studies.
momentum= mass × velocity = 0.141kg×1.33m/s= 0.18753kg m/s = 0.188kg m/s (3s.f.)
Answer:
2.67m/s
0.67m/s
Explanation:
Given parameters:
Number of laps run = 2.5laps
time taken = 75 sec
Diameter of track = 50m
Circumference = 120m
Unknown:
Average speed of runner = ?
Average velocity of runner = ?
Solution:
Average speed depends on the total distance traveled, it is the rate of change of distance with time. It covers the full extent of the path;
Average speed =
distance = circumference
Average speed = = 2.67m/s
Average velocity depends on the displacement at the end of the particular journey. The displacement deals with the length of path from start to finish in a specific direction.
The diameter is the same as displacement here.
Average velocity = = = 0.67m/s
To solve this problem we will use the relationship given between the centripetal Force and the Force caused by the weight, with respect to the horizontal and vertical components of the total tension given.
The tension in the vertical plane will be equivalent to the centripetal force therefore
Here,
m = mass
v = Velocity
r = Radius
The tension in the horizontal plane will be subject to the action of the weight, therefore
Matching both expressions with respect to the tension we will have to
Then we have that,
Rearranging to find the velocity we have that
The value of the angle is 14.5°, the acceleration (g) is 9.8m/s^2 and the radius is
Replacing we have that
Therefore the speed of each seat is 4.492m/s
Answer:
Explanation:
Capacitance is defined as the charge divided in voltage.
Introducing a dielectric into a parallel plate capacitor decreases its electric field. Therefore, the voltage decreases, as follows:
Where k is the dielectric constant and the voltage of the capacitor without a dielectric
The capacitance with a dielectric between the capacitor plates is given by:
Where k is the dielectric constant and the capacitance of the capacitor without a dielectric. So, we have:
Therefore, a capacitor with a dielectric stores the same charge as one without a dielectric.