Answer:
LT⁻¹
Explanation:
Assuming the given expression is
x = A t³ + B t.........(1)
x is the distance
we have to calculate dimension of dx/dt
from expression (1)
x = A t³
A = LT⁻³
x = B t
B = LT⁻¹
now,
dx/dt = 3At^2 + B
from rule of dimension
dimension of dx/dt is equal to dimension of At^2
dx/dt = A t²
dx/dt = LT⁻³ x T²
dx/dt = LT⁻¹
hence, dimension of dx/dt is equal to LT⁻¹
I think it is C because mass makes motion slower
Answer:
The forces are equal!
Explanation:
Both corks are subjected to the same buoyant force.
Answer:
Explanation:
Image formation by objective lens ,
f = focal length of objective = .75 cm, ( positive )
object distance u = .81 cm ( negative )
v = image distance
1/v - 1/u = 1/f
1/v + 1/.81 = 1 / .75
1/v = 1/ .75 - 1/.81 = .098765
v = 10.125.cm
Image formation by eye piece,
v = infinity ( for relaxed eye )
f ( eye piece ) = 2.70cm
u = ?
1/v - 1/u = 1/f
0 -1/u = 1/2.7
u = 2.7 cm
Total length between lenses
= 2.7 + 10.125
= 12.825 cm
Total magnification = m₁ x m₂
m₁ is magnification by objective and m₂ is magnification by eye piece
m₁ = v/u = 10.125 / .810 = 12.5
m₂ = 1 + D / f = 1 + 25 / 2.7 = 10.25
Total magnification
= 12.5 x 10.25 = 128.125