Downward force of magnitude 5 N is exerted on the book by the force of <em>gravity</em>. We call that the "weight" of the book.
At the same time, upward force of 5 N is exerted on the book by the table. This one is called the "normal force".
Since the vertical forces on the book are 'balanced' (add up to zero), the book just lays there on the table, and does not accelerate.
The figure mentioned on the question is in the attachment.
Answer: a)
= - 38.35N
b)
= 30.5 N
c)
= 27.45 N
d) a = - 13.16 m/s²
Explanation: A block on an inclined plane has 3 forces acting on it:
- Force due to gravity
= m.g; - Normal Force due to the plane;
- Force of Friction
= µ.N;
Since the plane is inclined, Normal Force is equal the y-component of the force due to gravity and Force of friction and the x-component of the force due to gravity are opposite forces.
The second attachment ilustrate the forces acting on the block.
Calculating:
A) The magnitude of the x-component of Force due to gravity:
According to the second image:
= P.sinθ
= 5.9.8.sin(36.8)
= - 38.35 N
B)
=
= m.g.cosθ
= 5.9.8.cos(36.8)
= 30.5 N
C)
= 0.9.30.5
= 27.45 N
D) For the acceleration, use Newton's Law:
= m . a
If there is movement, it is only on x-axis, so the net force is:
-
= m.a
- 38.35 - 27.45 = 5a
a = - 13.16 m/s²
The value of acceleration shows there is <u>no</u> <u>movement</u> on the x-axis due to the friction.
Answer:
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Explanation: sorry not sorry reases
The RC time constant, also called tau, the time constant (in seconds) of an RC circuit, is equal to the product of the circuit resistance (in ohms) and the circuit capacitance (in farads), i.e.

Here,
R = Resistance
C = Capacitance
Replacing we have that



Therefore the time constant of this circuit is 