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topjm [15]
3 years ago
10

If the dielectric constant is 14.1, calculate the ratio of the charge on the capacitor with the dielectric after it is inserted

as compared with the initial charge.
Physics
1 answer:
Lady bird [3.3K]3 years ago
7 0

Answer:

\frac{Q}{Q_0}=1

Explanation:

Capacitance is defined as the charge divided in voltage.

C=\frac{Q}{V}(1)

Introducing a dielectric into a parallel plate capacitor decreases its electric field. Therefore, the voltage decreases, as follows:

V=\frac{V_0}{k}

Where k is the dielectric constant and V_0 the voltage of the capacitor without a dielectric

The capacitance with a dielectric between the capacitor plates is given by:

C=kC_0

Where k is the dielectric constant and C_0 the capacitance of the capacitor without a dielectric. So, we have:

Q=CV\\Q=kC_0\frac{V_0}{k}\\Q=C_0V_0\\Q_0=C_0V_0\\Q=Q_0\\\frac{Q}{Q_0}=1

Therefore, a capacitor with a dielectric stores the same charge as one without a dielectric.

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A uniform electric field with a magnitude of 5750 N/C points in the positive x direction. Find the change in electric potential
castortr0y [4]

Explanation:

Given that,

Electric field = 5750 N/C

Charge q=+10.5\times10^{-6}\ C

Distance = 5.50 cm

(a). When the charge is moved in the positive x- direction

We need to calculate the change in electric potential energy

Using formula of electric potential energy

\Delta U=-W

\Delta U=-F\cdot d

\Delta U=-q(E\cdot d)

Put the value into the formula

\Delta U=-10.5\times10^{-6}\times5750\times5.50\times10^{-2}

\Delta U=-3.32\times10^{-3}\ J

The change in electric potential energy  is -3.32\times10^{-3}\ J

(b). When the charge is moved in the negative x- direction

We need to calculate the change in electric potential energy

Using formula of electric potential energy

\Delta U=-W

\Delta U=-F\cdot (-d)

\Delta U=-q(E\cdot (-d))

Put the value into the formula

\Delta U=-10.5\times10^{-6}\times5750\times(-5.50\times10^{-2})

\Delta U=3.32\times10^{-3}\ J

The change in electric potential energy  is 3.32\times10^{-3}\ J

Hence, This is the required solution.

3 0
3 years ago
A bomb of mass 6kg initially at rest explodes into two fragments of masses 4kg and2kg respectively. If the greater mass moves wi
Katen [24]

Answer:

v = 10 [m/s]

Explanation:

The largest mass is that of 4 [kg], in this way the momentum can be calculated by means of the product of the mass by velocity.

P=m*v\\

where:

P = momentum [kg*m/s]

m = mass = 4 [kg]

v = velocity = 5 [m/s]

Now the momentum:

P=4*5\\P=20[kg*m/s]

This same momentum is equal for the other mass, in this way we can find the velocity.

P=m*v\\20=2*v\\v=10[m/s]

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A constant horizontal force F is applied to a 5 kg box on a frictionless horizontal surface. The box starts from rest and moves
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65(58)+85)6463(9786+)9_43=
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How do waves interact with our senses?
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Answer:

well sound waves interact with our ears and light interacts with our vision

Explanation:

5 0
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Think and discuss: Why do you think the rate of temperature change does not stay constant over time? If possible, discuss your a
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