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Dafna11 [192]
3 years ago
8

A 0.141 kg pinewood derby car is moving 1.33 m/s . What is its momentum?

Physics
1 answer:
kompoz [17]3 years ago
7 0

momentum= mass × velocity = 0.141kg×1.33m/s= 0.18753kg m/s = 0.188kg m/s (3s.f.)

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A man weighing 700 NN and a woman weighing 440 NN have the same momentum. What is the ratio of the man's kinetic energy KmKmK_m
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Answer:

The ratio of the man's kinetic energy to that of the woman's kinetic energy is 0.629.

Explanation:

Given;

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P = mv\\\\v = \frac{P}{m}

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K_m = \frac{1}{2}m_m(\frac{P_m}{m_m})^2  \\\\K_m = \frac{P_m^2}{2m_m}

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P_w^2 = 2m_wK_w

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\frac{K_m}{K_w} = \frac{44.898}{71.429}\\\\\frac{K_m}{K_w} =0.629

Therefore, the ratio of the man's kinetic energy to that of the woman's kinetic energy is 0.629.

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\huge\boxed{♧ \: \mathfrak{ \underline{Answer} \: ♧}}

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