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Gekata [30.6K]
3 years ago
9

Ian has a mass of 58.0!kilograms. What is his weight?

Physics
2 answers:
dalvyx [7]3 years ago
6 0
The answer is About 127.87 pounds
Westkost [7]3 years ago
4 0
In newtons, which is the unit of weight in physics, gravitational force (aka weight) is mg. M=58.0kg, so 58(9.81)=568.98 or approx. 569 newtons.
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Larry weighs 300 N at the surface of Earth. What is the weight of Earth in the gravitational field of Larry
Setler [38]

The gravitational force of attraction between two objects is directly proportional to the product of the two masses and inversely proportional to the square of the distance between them.

F = \frac{GMm}{r^2}

Where,

G = Gravitational Universal Constant

M = Mass of the Planet

m = Mass of the object

r = Distance

Therefore the amount of force exerted by the first object on the second object is equal to the amount of the force exerted on the second object by the first.

The gravitational force exerted by Larry on the Earth is same as the force exerted on Larry by the Earth.

That is 300N.

4 0
3 years ago
Determine the amount of potential energy of a 5 newton book that is moved to three different shelves on a bookcase. The height o
BigorU [14]
Gravitational Potential Energy = weight x height

for 1 meter:

GPE = 5 x 1
 = <u>5N</u>

for 1.5 metres:

GPE = 5 x 1.5
 = <u>7.5N</u>

for 2 metres:

GPE = 5 x 2
 = <u>10N</u>
5 0
4 years ago
Why sheets of newspaper can be used to keep ice cream cold and keep fish and chips hot?
stich3 [128]

Answer: Paper

Explanation: It is a insulator

7 0
4 years ago
the imagine above shows to opposite forces acting on a rolling cart, what can we say is true about affect of the forces on the c
cluponka [151]

Answer:

Here is my answer...

Explanation:

The cart will connect with the opposite force, and then the cart will come to a shuddering stop before moving in the direction of the oposite force.

Hope I helped! :)

7 0
3 years ago
A rigid, 2.50 L bottle contains 0.458 mol He. The pressure of the gas inside the bottle is 1.83 atm. If 0.713 mol Ar is added to
stellarik [79]
<span>These are inert gases, so we can assume they don't react with one another. Because the two gases are also subject to all the same conditions, we can pretend there's only "one" gas, of which we have 0.458+0.713=1.171 moles total. Now we can use PV=nRT to solve for what we want.

The initial temperature and the change in temperature. You can find the initial temperature easily using PV=nRT and the information provided in the question (before Ar is added) and solving for T.

You can use PV=nRT again after Ar is added to solve for T, which will give you the final temperature. The difference between the initial and final temperatures is the change. When you're solving just be careful with the units!
 
SIDE NOTE: If you want to solve for change in temperature right away, you can do it in one step. Rearrange both PV=nRT equations to solve for T, then subtract the first (initial, i) from the second (final, f):

PiVi=niRTi --> Ti=(PiVi)/(niR)
 
PfVf=nfRTf --> Tf=(PfVf)/(nfR)

ΔT=Tf-Ti=(PfVf)/(nfR)-(PiVi)/(niR)=(V/R)(Pf/nf-Pi/ni)

In that last step I just made it easier by factoring out the V/R since V and R are the same for the initial and final conditions.</span>
8 0
3 years ago
Read 2 more answers
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