Which statement best describes Rutherford's model of the atom?

1. What is the kinetic energy of a 1.75 kg ball travelling at a speed of 54 m/s?

Over [174]

Answer:

We conclude that the kinetic energy of a 1.75 kg ball traveling at a speed of 54 m/s is 2551.5 J.

Explanation:

Given

Mass m = 1.75 kg

Velocity v = 54 m/s

To determine

Kinetic Energy (K.E) = ?

We know that a body can possess energy due to its movement — Kinetic Energy.

Kinetic Energy (K.E) can be determined using the formula

$K.E=\frac{1}{2}mv^2$

where

m is the mass (kg)

v is the velocity (m/s)

K.E is the Kinetic Energy (J)

now substituting m = 1.75, and v = 54 in the formula

$K.E=\frac{1}{2}mv^2$

$K.E=\frac{1}{2}\left(1.75\right)\left(54\right)^2$

$K.E=1458\times 1.75$

$K.E=2551.5$ J

Therefore, the kinetic energy of a 1.75 kg ball traveling at a speed of 54 m/s is 2551.5 J.

7 0

3 years ago

Although there are no glaciers in Florida , how have glaciers affected Florida?

Ksju [112]

They did not affect Florida- never came that far South.

5 0

3 years ago

In a laboratory, you determine that the density of a certain solid is 5.23×10−6kg/mm3. Convert this density into kilograms per c

kiruha [24]

Answer:

$5.23\cdot 10^3 kg/m^3$

Explanation:

The density of the solid is

$d = 5.23\cdot 10^{-6}kg/mm^3$

we want to convert it into kg/m^3. We must note that:

$1 m^3 = 1 m \cdot 1 m \cdot \1m =1000 mm\cdot 1000 mm \cdot 1000 mm=1\cdot 10^9 mm^3$

Therefore, the conversion can be done as follows:

$d=5.23\cdot 10^{-6} \frac{kg}{mm^3} \cdot (1\cdot 10^9 \frac{mm^3}{m^3}) =5.23\cdot 10^3 kg/m^3$

8 0

3 years ago

A rock is thrown horizontally out of a window with a velocity of 20.0 m/s. If the window is 8.50m above the ground, how far

vladimir1956 [14]

The distance from the base of the building the rock will land is 26.4 m

<h3>Data obtained from the question </h3>

Horizontal velocity (u) = 20 m/s
Height (h) = 8.50 m
Distance (s) =?

<h3>Determination of the time to reach the ground </h3>

Height (h) = 8.50 m
Acceleration due to gravity (g) = 9.8 m/s²
Time (t) =?

h = ½gt²

8.5 = ½ × 9.8 × t²

8.5 = 4.9 × t²

Divide both side by 4.9

t² = 8.5 / 4.9

Take the square root of both side

t = √(8.5 / 4.9)

t = 1.32 s

<h3>How to determine the distance </h3>

Horizontal velocity (u) = 20 m/s
Time (t) = 1.32 s
Distance (s) =?

s = ut

s = 20 × 1.32

s = 26.4 m

Learn more about motion under gravity:

brainly.com/question/22719691

6 0

3 years ago

Consider a 40,000 km steel pipe in the shape of a ring that fits snuggly all around the circumference of the Earth. We are heati

Tatiana [17]

Answer:

The Height is H = 70.02 m

Explanation:

We are given that the

Initial length is = $40000\ Km$ = $40,000 *10^{3} m$

from what we are told in the question the circumference of the circle is = $40,000 Km$

This means that the Radius would be :

Let C denote the circumference

So

$C = 2 \pi r$

=> $r = \frac{C}{2 \pi}$

$r = \frac{40,000}{2 \pi } = \frac{40,000*10^{3}}{2 *3.142} = 6.365*10^6 m$

We are told that 1-meter bar of steel that increases its temperature by 1 degree C will expand $11*10^{-6}$ meters

Hence

The final length would be

$40000*10^3 *(T + \alpha )$

Where T is the change in temperature $\alpha$ is the Coefficient of linear expansion for steel

let $L_{final}$ denote the final length

So

$L_{final} =40000*10^{6} *[1+ 11*10^{-6}]$

$= 40000440 \ m$

Now the Height is mathematically represented as

$Height(H) \ = \frac{change \ in \ radius \ }{2 \pi}$

$= \frac{(40000440-40000*10^3)}{2*3.142}$

$= 70.02m$

3 0

4 years ago