Question

The earth revolves around the sun in the counterclockwise direction, completing one full revolution about every 365 days. In reality the orbit is elliptical (with an eccentricity of 0.0167), but we’ll pretend that the orbit is a perfect circle. How many revolutions per day does the earth make around the sun? What is the angular velocity ωSE (radians/day) of the earth around the sun?

Answer 1

Answer:

Revolutions per day = 2.7 x 10⁻³ rev/day

ω = 1.72 x 10⁻² radians/day

Explanation:

It is given that the earth completes one revolution around the sun in 365 days. So, for the revolutions in one day we simply divide it by 365 days.

Revolutions per day = (No. of Revolutions)/(No. of Days)

Revolutions per day = 1 rev/365 days

Revolutions per day = 2.7 x 10⁻³ rev/day

The angular velocity is given as the ration of angular displacement to the time taken for the displacement. The formula for angular displacement is given as follows:

ω = θ/t

where,

ω = angular velocity = ?

θ = angular displacement = (1 rev)(2π rad/1 rev) = 2π radians

t = time = 365 days

Therefore,

ω = (2π radians)/(365 days)

ω = 1.72 x 10⁻² radians/day