|V| = 10.33 units and the direction θ = -47.35° or 312.65°.
Given the x and y components of a vector, we can calculate the magnitude and direction from these components.
Applying the Pythagorean theorem we have that the magnitude of the vector is:
|V| = 
|V| = 
The expression for the direction of a vector comes from the definition of the tangent of an angle:
tan θ =
------> θ = arc tan 
θ = arc tan 
θ = -47.35° or 312.65°
Answer:
force (tension) of 29.4 N (upward) in 100 cm
force (tension) of 58.4 N (upward) in 200 cm
Explanation:
Given:
Length of tube = 5 m (500 cm)
Mass of tube = 9
Suspended vertically from 150 cm and 50 cm.
Computation:
Force = Mass × gravity acceleration.
Force = 9.8 x 9
Force = 88.2 N
So,
Upward forces = Downward forces
D1 = 150 - 50 = 100 cm
D2 = 150 + 50 = 200 cm
And F1 = F2
F1 x D1 = F2 x D2
F1 x 100 = F2 x 200
F = 2F
Total force = Upward forces + Downward forces
3F = 88.2
F = 29.4 and 2F = 58.8 N
force (tension) of 29.4 N (upward) in 100 cm
force (tension) of 58.4 N (upward) in 200 cm
Answer:
Manganese (iv )oxide is a slow depolarizer and polarization occurs with a large current, on resting, the depolarization returns the p.d of the dry cell.
(a) 0.74 m/s^2
Explanation:
There are two forces acting on the skier: the component of the weight parallel to the slope, which acts downward, and the frictional force, which acts upward along the incline.
The component of the weight parallel to the inclined plane is:

where m is the mass of the skier,
and
.
The frictional force is instead

is the coefficient of friction for waxed wood on wet snow.
If we apply Newton's second law, we can write that the net force must be equal to the product of mass per acceleration:

And symplifying m, we can find the acceleration:


(b) 
Explanation:
This time, the skier is moving at constant velocity. Therefore, the acceleration is zero (a=0) and Newton's second law becomes:

By simplifying, we get

From which we can find the angle at which the skier could coast at a constant velocity:

Answer:
10392.30N
Explanation:
We proceed by computing the individual force exerted by the boats
For the first boat
The angle is 30 degree to the vertical
Hence
Force = F cos θ
F=6000 cos 30
F=6000*0.866
F=5196.15 N
Since the boats are two and also at the same angle and also exerting the same force
The Net force = 2*5196.15
Net force=10392.30N