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Sloan [31]
3 years ago
7

Please answer this correctly

Mathematics
2 answers:
klasskru [66]3 years ago
6 0

Answer:

3/4

Step-by-step explanation:

3/4 + 1/4 = 4/4 ( the whole cake )

so 4/4 - 1/4 = 3/4

Leya [2.2K]3 years ago
6 0

Answer:

3/4

Step-by-step explanation:

Darnel's friends ate 3/4 of the cake.

1/4+3/4=4/4=1 whole

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Can some won help me pls
exis [7]

Answer:

Just see how are they alike and differents

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
30+ Points!!!<br> 5. Solve the following inequalities.<br> a) 2 log3x – 2 logx3 -3 &lt;0
Ilya [14]

Answer:

I answered your last question also

2 log3x – 2 logx3 -3 <0

\mathrm{Subtract\:}2\log ^3\left(x\right)\mathrm{\:from\:both\:sides}

2\log ^3\left(x\right)-2logx^3-3-2\log ^3\left(x\right)

\mathrm{Simplify}

-2logx^3-3

\mathrm{Add\:}3\mathrm{\:to\:both\:sides}

-2logx^3-3+3

\mathrm{Simplify}

-2logx^3

Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)

\left(-2logx^3\right)\left(-1\right)>-2\log ^3\left(x\right)\left(-1\right)+3\left(-1\right)

\mathrm{Simplify}

2lx^3og>2\log ^3\left(x\right)-3

\mathrm{Divide\:both\:sides\:by\:}2lx^3o;\quad \:l>0

\frac{2lx^3og}{2lx^3o}>\frac{2\log ^3\left(x\right)}{2lx^3o}-\frac{3}{2lx^3o};\quad \:l>0\\

\mathrm{Simplify}

g>\frac{2\log ^3\left(x\right)-3}{2lx^3o};\quad \:l>0

Step-by-step explanation:

6 0
3 years ago
Plz help me well mark brainliest if correct!!..
zepelin [54]

Answer: A/The LINE graph

Step-by-step explanation:

6 0
3 years ago
Suppose that you saw 240 minutes of commercials this week. How many hours of commercials did you see?
kicyunya [14]

Answer:

4 hours

Step-by-step explanation:

240÷60=4 hours

3 0
3 years ago
.........................
Zigmanuir [339]

Answer:

A

Step-by-step explanation:

given 3xy + 4yz + 8xz = 10

subtract 8xz from both sides leaving the terms in y together

3xy + 4yz = 10 - 8xz

take out the common factor y on the left side

y(3x + 4z) = 10 - 8xz

divide both sides by (3x + 4z)

y = \frac{10-8xz}{3x+4z} → A


5 0
3 years ago
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