See attached picture for the missing image required to answer the question.
Answer: 4/21
Step-by-step explanation:
Total number of tiles(possible outcomes) = 7
Number of green tiles(required outcomes) =2
Number of Blue tiles(required outcomes) = 4
Recall :
Probability (P) = Required outcome / total possible outcomes
First pick (without replacement) :
P(picking a green tile) = 2/7
Second pick :
Tiles left after first pick = 6
P(picking a blue tile) = 4/6 = 2/3
Compound probability :
P(picking a green tile) × p(picking a blue tile)
(2/7) × (2/3) = 4/21
Answer:
<em>Its 43.2 </em>
<em></em>
<em>I hope this helps ^^</em>
I think it's a, c or e since those are all close to ten but you could use a ruler
<span>(f+g)(x) if f(x)=2/x+1 and g(x)=x-2
Add f and g together: (f+g)(x) = (2/x) + 1 + x - 2 = (2/x) + x - 1</span>
Check the picture below.
so the shape is really 4 triangles with a base of 2 and a height of 4 each, and 2 squares tha are 4x4.
![\bf \stackrel{\textit{area of the 4 triangles}}{4\left[\cfrac{1}{2}(2)(4) \right]}~~+~~\stackrel{\textit{area of the two squares}}{2(4\cdot 4)}\implies 16+32\implies 48](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B%5Ctextit%7Barea%20of%20the%204%20triangles%7D%7D%7B4%5Cleft%5B%5Ccfrac%7B1%7D%7B2%7D%282%29%284%29%20%5Cright%5D%7D~~%2B~~%5Cstackrel%7B%5Ctextit%7Barea%20of%20the%20two%20squares%7D%7D%7B2%284%5Ccdot%204%29%7D%5Cimplies%2016%2B32%5Cimplies%2048)