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evablogger [386]
3 years ago
15

A ball is falling after rolling off a tall roof. The ball has what type of energy.

Physics
1 answer:
Firlakuza [10]3 years ago
7 0

Answer:

Correct answer: Kinetic energy of rotation, kinetic energy of translation and potential energy

Explanation:

Before it began to rotate it possessed potential energy. After being released from the rest it starts to roll on the roof and get kinetic energy of rotation, kinetic energy of translation along with potential energy.

God is with you!!!

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A common carnival ride, called a gravitron, is a large r = 11 m cylinder in which people stand against the outer wall. the cylin
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Answer:

The minimum speed is 14.53 m/s.

Explanation:

Given that,

r = 11 m

Friction coefficient = 0.51

Suppose we need to find the minimum speed, that the cylinder must make a person move at to ensure they will stick to the wall

When frictional force becomes equal to or greater than the weight of person

Then, he sticks to the wall

We need to calculate the minimum speed

Using formula for speed

f_{s}=\mu N\geq mg

Where, N =\dfrac{mv^2}{r}

\mu\times\dfrac{mv^2}{r}\gep mg

v^2\geq\dfrac{gr}{\mu}

Put the value into the formula

v=\sqrt{\dfrac{9.8\times11}{0.51}}

v=14.53\ m/s

Hence, The minimum speed is 14.53 m/s.

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A horizontal spring with spring constant 950 N/m is attached to a wall. An athlete presses against the free end of the spring, c
OLga [1]

Answer:

66.5N

Explanation:

F = kx

Where F = force

K = spring constant

x = compression

Given

K = 950N/m

x = 7.0cm

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7.0cm = 7.0 x 0.01

= 0.07 meters

Therefore

F = 950 x 0.07

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as earth rotates about it’s axis, it takes three hours for the united states to pass beneath a point above earth that is station
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A combination lock has a 1.3-cm-diameter knob that is part of the dial you turn to unlock the lock. To turn that knob, you twist
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Answer:

0.04225 Nm

Explanation:

N = Force applied = 5 N

\mu = Coefficient of static friction = 0.65

d = Diameter of knob = 1.3 cm

r = Radius of knob = \frac{d}{2}=\frac{1.3}{2}=0.65\ cm

Force is given by

F=N\mu\\\Rightarrow F=5\times 0.65\\\Rightarrow F=3.25\ N

When we multiply force and radius we get torque

Torque on thumb

\tau_t=F\times r\\\Rightarrow \tau_t=3.25\times 0.0065\\\Rightarrow \tau_t=0.021125\ Nm

Torque on forefinger

\tau_f=F\times r\\\Rightarrow \tau_f=3.25\times 0.0065\\\Rightarrow \tau_f=0.021125\ Nm

The total torque is given by

\tau=\tau_t+\tau_f\\\Rightarrow \tau=0.021125+0.021125\\\Rightarrow \tau=0.04225\ Nm

The most torque that exerted on the knob is 0.04225 Nm

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