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evablogger [386]
3 years ago
15

A ball is falling after rolling off a tall roof. The ball has what type of energy.

Physics
1 answer:
Firlakuza [10]3 years ago
7 0

Answer:

Correct answer: Kinetic energy of rotation, kinetic energy of translation and potential energy

Explanation:

Before it began to rotate it possessed potential energy. After being released from the rest it starts to roll on the roof and get kinetic energy of rotation, kinetic energy of translation along with potential energy.

God is with you!!!

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When numbers are very small or very large, it is convenient to either express the value in scientific notation and/or by using a
Oxana [17]

Answer:

5 mg, 5\cdot 10^{-3}g

Explanation:

First of all, let's rewrite the mass in grams using scientific notation.

we have:

m = 0.005 g

To rewrite it in scientific notation, we must count by how many digits we have to move the dot on the right - in this case three. So in scientific notation is

m=5\cdot 10^{-3}g

If  we want to convert into milligrams, we must remind that

1 g = 1000 mg

So we can use the proportion

1 g : 1000 mg = 0.005 g : x

and we find

x=\frac{(1000 mg)(0.005 g)}{1 g}=5 mg

4 0
3 years ago
The sense of equilibrium responds to movements of the head. It is divided into two types--static and dynamic equilibrium. Descri
Sonja [21]

Answer:

nodding of head ,yes- static equilibrium

nodding of head, no- dynamic equilibrium.

Explanation:

static equilibrium monitors head position when body is not moving .

dynamic equilibrium monitors the angular or rotational movements of the head when body moves.

5 0
3 years ago
Read 2 more answers
1. You released a pendulum of mass 1kg from a height of 0.05m
photoshop1234 [79]

a. The speed of the pendulum when it reaches the bottom is 0.9 m/s.

b. The height reached by the pendulum is 0.038 m.

c. When the pendulum no longer swing at all, all the kinetic energy of the pendulum has been used to overcome frictional force.

<h3>Kinetic energy of the pendulum when it reaches bottom</h3>

K.E = 100%P.E - 18%P.E

where;

  • P.E is potential; energy

K.E(bottom) = 0.82P.E

K.E(bottom) = 0.82(mgh)

K.E(bottom) = 0.82(1 x 9.8 x 0.05) = 0.402 J

<h3>Speed of the pendulum</h3>

K.E = ¹/₂mv²

2K.E = mv²

v² = (2K.E)/m

v² = (2 x 0.402)/1

v² = 0.804

v = √0.804

v = 0.9 m/s

<h3>Final potential energy </h3>

P.E = 100%K.E - 7%K.E

P.E = 93%K.E

P.E = 0.93(0.402 J)

P.E = 0.374 J

<h3>Height reached by the pendulum</h3>

P.E = mgh

h = P.E/mg

h = (0.374)/(1 x 9.8)

h = 0.038 m

<h3>when the pendulum stops</h3>

When the pendulum no longer swing at all, all the kinetic energy of the pendulum has been used to overcome frictional force.

Thus, the speed of the pendulum when it reaches the bottom is 0.9 m/s.

The height reached by the pendulum is 0.038 m.

When the pendulum no longer swing at all, all the kinetic energy of the pendulum has been used to overcome frictional force.

Learn more about pendulum here: brainly.com/question/26449711
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5 0
2 years ago
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allochka39001 [22]
Firs people love sports because of culture
8 0
3 years ago
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A fire hose held near the ground shoots water at a speed of 6.5 m/s. at what angle(s) should the nozle point in order that the w
VladimirAG [237]
 <span>The trajectory (parabola) for a "particle" of water follows from: 


h(t) = v(0) sin(angle) t - 1/2 g t^2 


x(t) = v(0) cos(angle) t 


From the second equation t = x / (v(0) cos(angle) ) 
and substitution in the first to eliminate t gives the parabola h(x): 


h(x) = x tan(angle) - (g/(2v(0)^2 cos(angle)^2) x^2 


h(x) = 0 is solved by x=0 (where the trajectory starts) and at 


x = 2 v(0)^2 tan(angle) cos^2(angle) / g 


x = 2 v(0)^2 sin(angle) cos(angle) / g 


x = v(0)^2 sin(2 angle) / g [[ using sin(2 ) = 2 sin(s) cos(s) ]] 


For the first question (the 2.0m distance question) you have therefore to solve for angle the equation 

2.0= 2*(6.5)^2 sin(2 angle) / 9.81 


sin(2 angle) = 0.23

angle = 1/2 * arcsin(0.23) = 6.65 degrees 


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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3 0
3 years ago
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