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ElenaW [278]
2 years ago
8

The sense of equilibrium responds to movements of the head. It is divided into two types--static and dynamic equilibrium. Descri

be and give an example of these two types of equilibrium. Select all the statements that accurately describe equilibrium.
Physics
2 answers:
Sonja [21]2 years ago
5 0

Answer:

nodding of head ,yes- static equilibrium

nodding of head, no- dynamic equilibrium.

Explanation:

static equilibrium monitors head position when body is not moving .

dynamic equilibrium monitors the angular or rotational movements of the head when body moves.

SpyIntel [72]2 years ago
4 0

Answer: Static equilibrium is simply described as one in which all forces acting on an object are balanced which implies that there is no resultant forces. And the object is not in motion releative to the reference plane.i.e the object does not have a velocity.

While

Dynamic equilibrium is type of equilibrium in which all the forces acting on an object are balanced but the object it moving, i.e there exist a veleocity.

Explanation:

Equilibrium simply means, forces are in balance. i.e the net force should be zero.

It can further explained forces acting downward and acting upward, and forces acting right and acting left should be equal in magnitude.

1) dynamic equilibrium can be described as the one in which the reactants are converted to products and products are converted to reactants at an equal and constant rate. Equilibrium is the state of equal, opposite rates, not equal concentrations.

Examples of dynamic equilibrium are; a)a car moving at constant velocity, b)a fan rotating at uniform speed

2)Static equilibrium is the one in which the rate of forward process is equal to reverse process.It is usually regarded as MECHANICAL EQUILIBRIUM because it occurs when all particles in the reaction are at rest and there is no motion between reactants and products.

Static equilibrium can be noticed when there is a steady-state in a system that is the dynamic forces are not acting on the potential energies of the reverse and forward reactions.

An example of static equilibrium is when graphite turn into diamond, and it is illustrated as

C(diamond) ⇌ C(graphite)

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sweet-ann [11.9K]
B,
the reaction according to Newton’s third law must be an equal and opposite reaction. The force will be greater in order to bounce off of Doug’s bat
6 0
2 years ago
A fluid is flowing through a circulat tube at 0.4 kg/s. Tube inner surface is smooth with a diameter 0.014 m. Fluid density is 9
ElenaW [278]

Answer:

The convection coefficient is 15456.48\ W/m^{2}K

Solution:

Mass flow rate, \dot{m} = 0.4\ kg

Inner diameter of the tube, d = 0.014 m

Fluid density, \rho_{f} = 990\ kg/m^{3}

Specific Heat, C = 3845 J/K

Thermal Conductivity, K = 0.74

Prandtl Number, P_{r} = 8.6

Heat flux, \dot{q} = 71,297\ W/m^{2}

Viscosity, \mu = 0.00079\ Ns/m^{2}

Now,

To calculate the convection heat coefficient, h:

Determine the cross sectional area of the circular tube:

A_{c} = \frac{\pi}{4}d^{2} = \frac{\pi}{4}\times (0.014)^{2} = 1.54\time 10^{- 4}\ m^{2}

Determine the velocity of the fluid inside the tube by mass flow rate:

\dot{m} = \rho_{f}A_{c}v

0.4 = 990\times 1.54\time 10^{- 4}v

v = 2.624 m/s

Determine the Reynold's Number, R_{e}:

R_{e} = \frac{\rho_{f}dv}{\mu}

R_{e} = \frac{990\times 0.014\times 2.624}{0.00079} = 46036.253

Thus it is clear that R_{e} > 10,000 hence flow is turbulent.

Now,

Determine the Nusselt Number:

N_{u} = 0.023R_{e}^{0.8}P_{r}^{0.4}

N_{u} = 0.023\times 46036.253^{0.8}\times 8.6^{0.4} = 292.42

Also,

N_{u} = \frac{dh}{K}

where

h = convection coefficient

Now,

292.42 = \frac{0.014\times h}{0.74}

h = 15456.48\ W/m^{2}K

7 0
3 years ago
Please help me I’ll mark brainless .
Ivan
The mass is 10.811 hope this helps
7 0
2 years ago
Calculate the magnitude of the acceleration due to gravity on the surface of Earth due to the Moon.
Fudgin [204]

Answer:

g'_h=1.096\times 10^{-5}\ m.s^{-2}

Explanation:

We know that the gravity on the surface of the moon is,

  • g'=\frac{g}{6}
  • g'=1.63\ m.s^{-2}

<u>Gravity at a height h above the surface of the moon will be given as:</u>

g'_h=\frac{G.m}{(r+h)^2} ..........................(1)

where:

G = universal gravitational constant

m = mass of the moon

r = radius of moon

We have:

  • G=6.67\times 10^{-11}\ m^3.s^{-2}.kg^{-1}
  • m=7.35\times 10^{22}\ kg
  • r=1.74\times 10^6\ m
  • h=384.4\times 10^6\ m is the distance between the surface of the earth and the moon.

Now put the respective values in eq. (1)

g'_h=\frac{6.67\times 10^{-11}\times 7.35\times 10^{22}}{(1.74\times 10^6+384.4\times 10^6)^2}

g'_h=1.096\times 10^{-5}\ m.s^{-2} is the gravity on the moon the earth-surface.

4 0
3 years ago
A boat travels north across a river at a velocity of 22 meters/second with respect to the water. The river's velocity is 2.2 met
MArishka [77]
The magnitude of the resultant is

         √ (22² + 2.2²)  =  √ (484 + 4.84)  =  √488.84  =  22.11 m/s .

The direction of the resultant is

         tan⁻¹(22N / 2.2E)  =  tan⁻¹(10)  =  5.71° east of north .
7 0
3 years ago
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