Answer:
Surely Achilles will catch the Tortoise, in 400 seconds
Explanation:
The problem itself reduces the interval of time many times, almost reaching zero. However, if we assume the interval constant, then it is clear that in two hours Achilles already has surpassed the Tortoise (20 miles while the Tortoise only 3).
To calculate the time, we use kinematic expression for constant speed:

The moment that Achilles catch the tortoise is found by setting the same final position for both (and same time as well, since both start at the same time):

Answer:
547 m
Explanation:
From law of motion
s = ut + ½at²
Where "t" is Time taken to reach Earth
s= distance= 182 m
a= vertical acceleration = 5.82 m / s 2
U= initial velocity in vertical position = 0
182= ½ × 5.82t²
t²=( 2× 182)/ 5.82
= 364/5.82
= 62.54
t= √62.54
t= 7.908s
horizontal distance travelled = speed x time
Horizontal speed= 72.6 m / s
horizontal distance travelled =72.6× 7.908
= 547 m
Hence, the survivor will it hit the waves at 547 m away
A :-) for this question , we should apply
F = ma
( i ) Given - m = 2 kg
a = 15 m/s^2
Solution :
F = ma
F = 2 x 15
F = 30 N
( ii ) Given - m = 2 kg
a = 10 m/s^2
Solution :
F = ma
F = 2 x 10
F = 20 N
.:. The net force of object ( i ) has greater force compared to object ( ii ) by
( 30 - 20 ) 10 N
The right answer is B. hope this helps you :)
Failed experiments, uncontrolled variables, invalid data, and generalized human error