Why are two balls connected by a spring a good model for two atoms connected by a chemical bond?

1 answer:

8 0

Why are two balls connected by a spring a good model for two atoms connected by a chemical bond? (a) If the two atoms get farther apart than the equilibrium interatomic distance, they attract each other. (b) Each spring represents a real microscopic coiled metal wire that connects two adjacent atoms. If the two atoms get closer together than the equilibrium interatomic distance, they repel each other. (c) The magnitude of the force one atom exerts on another is proportional to the stretch or compression of the bond between them

Answer:

all the three options are correct

Explanation:

if the two atoms get closer together than the equilibrium inter atomic distance, they repel each other.

If the two atoms get farther apart than the equilibrium inter atomic distance, they attract each other.

The magnitude of the force one atom exerts on another is proportional to the stretch or compression of the bond between them

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Can someone help me?!!!!!

german

<h2>Hello!</h2>

The answer is:

The first option, the walker traveled 360m more than the actual distance between the start and the end points.

Why?

Since each block is 180 m long, we need to calculate the vertical and the horizontal distance, in order to calculate how farther did the travel walk between the start and the end points (displacement).

So, calculating we have:

Traveler:

$Distance=NorthCoveredDistance+EastCoveredDistance$

$Distance=4*180m+3*180m=720m+540m=1260m$

Actual distance between the start and the end point (displacement):

$ActualDistance=\sqrt{NorthDistance+EastDistance}\\\\ActualDistance=\sqrt{NorthDistance^{2} +EastDistance^{2}}\\\\ActualDistance=\sqrt{(720m)^{2} +(540m)^{2}}\\\\ActualDistance=\sqrt{518400m^{2} +291600m^{2}}\\\\ActualDistance=\sqrt{810000m^{2}}=900m$

Now, to calculate how much farter did the traveler walk, we need to use the following equation:

$DistanceDifference=WalkerCoveredDistance-ActualDistance\\\\DistanceDifference=1260m-900m=360m$

Therefore, we have that distance differnce between the distance covered by the walker and the actual distance is 360m.

Hence, we have that the walker traveled 360m more than the actual distance between the start point and the end point.

Have a nice day!

3 0

3 years ago

A transformer is designed to provide 6 V from a 150 V supply. If the primary coil has 1000 turns, how many turns does the second

zavuch27 [327]

The applicable relationship is N1/N2 = V1/V2, meaning the ratio of primary voltage to secondary voltage is equal to the ratio of primary turns to secondary turns.

Here N1 = 1000, V1 = 250, V2 = 400V and N2 = TBD.

Rewriting the above relationship, N2 = N1 V2/V1 = 1000 x 400/250 = 1600 turns.

7 0

2 years ago

What is the speed of a wave that has a frequency of 125 Hz and a wavelength of 1.25 meters?

kirill115 [55]

Using the "v = f. λ" <span>equation...

Your "v" or </span>velocity = 156.25 meters/second

5 0

3 years ago

Need help solving this

Nostrana [21]

Answer:

cant see picture

Explanation: