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3 years ago

Why are two balls connected by a spring a good model for two atoms connected by a chemical bond?

1 answer:

8 0

Why are two balls connected by a spring a good model for two atoms connected by a chemical bond? (a) If the two atoms get farther apart than the equilibrium interatomic distance, they attract each other. (b) Each spring represents a real microscopic coiled metal wire that connects two adjacent atoms. If the two atoms get closer together than the equilibrium interatomic distance, they repel each other. (c) The magnitude of the force one atom exerts on another is proportional to the stretch or compression of the bond between them

Answer:

all the three options are correct

Explanation:

if the two atoms get closer together than the equilibrium inter atomic distance, they repel each other.

If the two atoms get farther apart than the equilibrium inter atomic distance, they attract each other.

The magnitude of the force one atom exerts on another is proportional to the stretch or compression of the bond between them

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Please help homework due tomorrow,,,

Ad libitum [116K]

Cody ...

Everything on this page is solved with the SAME formula !

Distance = (speed) x (time) .

Before I get into how to solve each problem, we need to notice that
this whole sheet deals with speed, NOT velocity.

'Velocity' is speed AND THE DIRECTION OF THE MOTION.
Nothing on this page ever mentions direction, so there's no velocity
anywhere on the page.

Your teacher may not be happy if you talk about this on your homework,
but that's too bad. Just don't say "velocity" in any of your answers.
Say "speed", and if the teacher complains about that, then it's time to
let the teacher have it with both barrels.

1). Speed = (distance covered) / (time to cover the distance)

2). Speed = (distance covered) / (time to cover the distance)

3). Distance = (average speed of travel) x (time traveling at that speed)

4). Time to cover the distance = (distance) / (speed)

5). Car's speed = (distance the car covered) / (time the car took)
Sprinter speed = (distance the sprinter covered) / (time the sprinter took)

Calculate the car's speed.
Calculate the sprinter's speed.

... Look at the two speeds.
Decide which one is faster.

... Subtract the slower one from the faster one.
The difference is the answer to "by how much?" .

6). Distance = (speed) x (time spent moving at that speed)

7). Average speed = (TOTAL distance covered)
divided by
(time to cover the TOTAL distance).

8 0

3 years ago

Un cuerpo se mueve con MRU a una rapidez de 12 m/s y recorre 240 m; luego, disminuye su ra¬pidez uniformemente a razón de 2 m/s2

Annette [7]

Answer:

29 seconds

Explanation:

First we have a constant speed of 12 m/s and the distance of 240 m, so to find the time we can use the formula:

distance = speed * time

240 = 12 * time1

time1 = 20 seconds

Then, the speed decreases at 2 m/s2 until it reaches 2 m/s. So to find this time, we use this formula:

Final speed = inicial speed + acceleration * time

2 = 12 - 2 * time2

2*time2 = 10

time2 = 5 seconds.

Then, the speed increases from 2 m/s to 22 m/s with an acceleration of 5 m/s2, so we have:

Final speed = inicial speed + acceleration * time

22 = 2 + 5 * time3

5*time3= 20

time3 = 4 seconds

The total time is:

Total time = time1 + time2 + time3 = 20 + 5 + 4 = 29 seconds

7 0

3 years ago

Use newton's laws to find an expression for the net external force acting on the car. ignore air resistance.

alexira [117]

Hi, thank you for posting your question here at Brainly.

Newton's second law of motion can be expressed as Fnet = ma. The next external for acting on, say for example, a moving car are the following:

*weight due to gravity (force down)
*friction force between he road and the car's tires (force opposite the car's direction)

4 0

2 years ago

Use the work-energy theorem to determine the force required to stop a 1000 kg car moving at a speed of 20.0 m/s if there is a di

Vlad1618 [11]

Answer:

4.44 kN in the opposite direction of acceleration.

Explanation:

Given that, the initial speed of the car is, $u=20m/s$

And the mass of the car is, $m=1000 kg$

The total distance covered by the car before stop, $s=45m$

And the final speed of the car is, $u=0m/s$

Now initial kinetic energy is,

$KE_{i}=\frac{1}{2}mu^{2}$

Substitute the value of u and m in the above equation, we get

$KE_{i}=\frac{1}{2}(1000kg)\times (20)^{2}\\KE_{i}=20000J$

Now final kinetic energy is,

$KE_{f}=\frac{1}{2}mv^{2}$

Substitute the value of v and m in the above equation, we get

$KE_{f}=\frac{1}{2}(1000kg)\times (0)^{2}\\KE_{i}=0J$

Now applying work energy theorem.

Work done= change in kinetic energy

Therefore,

$F.S=KE_{f}-KE_{i}\\F\times 45=(0-200000)J\\F=\frac{-200000J}{45}\\ F=-4444.44N\\F=-4.44kN$

Here, the force is negative because the force and acceleration in the opposite direction.

6 0

2 years ago

How could you increase the gravitational potential energy between yourself and Earth?

Tamiku [17]

Gravitational Potential Energy, GPE = mgh

Where m is your mass in kg, g is acceleration due to gravity = 9.8 m/s², and h is the height in m.

The only value that be controlled here is the height h. The mass is constant, and acceleration due to gravity at that place is constant.

But h can be varied.

Hence to increase the gravitational potential energy between yourself and Earth is to increase the height h.

This can be done by climbing up a table, or climbing up a building through the stairs, or by using a lift.

5 0

2 years ago