1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
natulia [17]
2 years ago
6

1. You released a pendulum of mass 1kg from a height of 0.05m

Physics
1 answer:
photoshop1234 [79]2 years ago
5 0

a. The speed of the pendulum when it reaches the bottom is 0.9 m/s.

b. The height reached by the pendulum is 0.038 m.

c. When the pendulum no longer swing at all, all the kinetic energy of the pendulum has been used to overcome frictional force.

<h3>Kinetic energy of the pendulum when it reaches bottom</h3>

K.E = 100%P.E - 18%P.E

where;

  • P.E is potential; energy

K.E(bottom) = 0.82P.E

K.E(bottom) = 0.82(mgh)

K.E(bottom) = 0.82(1 x 9.8 x 0.05) = 0.402 J

<h3>Speed of the pendulum</h3>

K.E = ¹/₂mv²

2K.E = mv²

v² = (2K.E)/m

v² = (2 x 0.402)/1

v² = 0.804

v = √0.804

v = 0.9 m/s

<h3>Final potential energy </h3>

P.E = 100%K.E - 7%K.E

P.E = 93%K.E

P.E = 0.93(0.402 J)

P.E = 0.374 J

<h3>Height reached by the pendulum</h3>

P.E = mgh

h = P.E/mg

h = (0.374)/(1 x 9.8)

h = 0.038 m

<h3>when the pendulum stops</h3>

When the pendulum no longer swing at all, all the kinetic energy of the pendulum has been used to overcome frictional force.

Thus, the speed of the pendulum when it reaches the bottom is 0.9 m/s.

The height reached by the pendulum is 0.038 m.

When the pendulum no longer swing at all, all the kinetic energy of the pendulum has been used to overcome frictional force.

Learn more about pendulum here: brainly.com/question/26449711
#SPJ1

You might be interested in
A ball of mass m on a string of length L is attached to a pivot. The ball is released from rest while the string is parallel to
mash [69]

Answer:

L/2

Explanation:

Neglect any air or other resistant, for the ball can wrap its string around the bar, it must rotate a full circle around the bar. This means the ball should be able to swing to the top position where it's directly above the bar. By the law of energy conservation, this happens when the ball is at the same level as where it's previously released vertically. It means the swinging radius around the bar must be at least half of the string length.

So the distance d between the bar and the pivot should be at least L/2

8 0
3 years ago
Naphthalene combustion can be used to calibrate the heat capacity of a bomb calorimeter. the heat of combustion of naphthalene i
barxatty [35]
My namer js gpvjt ahsdhhsdbdb
6 0
3 years ago
1.10) For a fixed mass of gas at constant temperature, if the volume of the gas (V) increases to twice its original amount, the
Aliun [14]
B. 1/2p
From the relation
P1V1=P2V2
P2=P1V1/V2
If everything equals one
P2=1*1/2(1)
That would equal 1/2
I hope this helps
Please mark as brainliest
7 0
3 years ago
Read 2 more answers
Given that a pipe having a diameter of 1.5 feet and a height of 10 feet, what is the psi at 5 feet ?
grin007 [14]

Answer:

The pressure is 2.167 psi.

Explanation:

Given that,

Diameter = 1.5 feet

Height = 10 feet

We need to calculate the psi at 5 feet

Using formula of pressure at a depth in a fluid

Suppose the fluid is water.

Then, the pressure is

P=\rho g h

Where, P = pressure

\rho = density

h = height

Put the value into the formula

P=1000\times9.8\times1.524

P=14935.2\ N/m^2

Pressure in psi is

P=2.166167621\ psi

P=2.167\ psi

Hence, The pressure is 2.167 psi.  

4 0
3 years ago
What is the escape speed of an electron launched from the surface of a 1.1-cm-diameter glass sphere that has been charged to 8.0
zimovet [89]
At surface,
v = kq/r

And potential energy of an electron is given by,
PE = -ev = -ekq/r

At escape velocity,
PE + KE = 0.
Therefore,
1/2mv^2 - ekq/r =0
1/2mv^2 = ekq/r
v = Sqrt [2ekq/mr], where v = escape velocity, e = 1.6*10^-19 C, k = 8.99*10^9 Nm^2/C^2, m = 9.11*10^-31 kg, r = 1.1*10^-2 m, q = 8*10^-9 C

Substituting;
v = Sqrt [(2*1.6*19^-19*8.99*10^9*8*10^-9)/(9.11*10^-31*1.1*10^-2)] = 47949357.23 m/s ≈ 4.795 *10^7 m/s
5 0
3 years ago
Other questions:
  • Two boys want to balance a seesaw perfectly. One boy weighs 120 pounds and is sitting four feet from the fulcrum. The other boy
    7·1 answer
  • (30 points) Air enters a compressor at 1 bar, 310 K, and is compressed adiabatically to 12 bar, 630 K. The air exiting the compr
    7·1 answer
  • Can something have energy without having momentum? explain. can something have momentum without having energy? defend your answe
    15·1 answer
  • A car moving at constant speed in a straight line with the engine providing a driving force equal to the resistive force F.
    11·2 answers
  • Idaho Jo is doing physics experiments throughout the solar system. She travels to each planet and shoots a potato straight up in
    15·1 answer
  • Two linear polarizing filters are placed one behind the other, so that their transmission directions are parallel to one another
    11·1 answer
  • A regular polygon has angkes of size 150° each.how many side has the polygon​
    8·1 answer
  • Red light has a wavelength of 500 nm. What is the frequency of red light?
    14·1 answer
  • a steel sphere and brass ring have diameter 25cm and 24.9cm at 15°C.If the sphere and the ring are heated together.what is the t
    14·1 answer
  • How is property belonging to individuals protected under the Fifth Amendment?
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!