First you write the "molecular" equation, then the ionic equation, and finally the net ionic equation.
Explanation:
You can read about these equations at
Here are the steps for your reaction.
1. Write the molecular equation
We write the equation as if all the reactants were molecules.
2HNO₃(aq) + Mg(OH)₂(s) → 2H₂O(l) + Mg(NO₃)₂(aq
2. Write the ionic equation
We write all the soluble strong electrolytes as ions. H₂O is a weak electrolyte, so we write it as a molecule. Mg(OH)₂ is insoluble, so we write it as a molecule as well.
2H⁺(aq) + 2NO₃⁻(aq) + Mg(OH)₂(s) → 2H₂O(l) + Mg²⁺(aq) + 2NO₃⁻(aq)
3. Write the net ionic equation
Here, we cancel all species that appear on both sides of the equation. We cancel the NO₃⁻ ions.
The net ionic equation is
2H⁺(aq) + Mg(OH)₂(s) → 2H₂O(l) + Mg²⁺(aq)
Answer:
124.56 moles of Hydrogen atoms.
Explanation:
We'll begin by calculating the number of moles of ethane that contains 1.25×10²⁵ molecules. This can be obtained as follow:
From Avogadro's hypothesis, 1 mole of any substance contains 6.02x10²³ molecules. This implies that 1 mole of ethane also contains 6.02x10²³ molecules.
Thus, 6.02x10²³ molecules are present in 1 mole of ethane.
Therefore, 1.25×10²⁵ molecules are present in = 1.25×10²⁵/6.02x10²³ = 20.76
Therefore, 20.76 moles of ethane contains 1.25×10²⁵ molecules.
Finally, we shall determine the number of mole of Hydrogen in 20.76 moles of ethane. This can be obtained as follow:
Ethane has formula as C2H6.
From the formula, 1 mole of ethane, C2H6 contains 6 moles of Hydrogen atoms.
Therefore, 20.76 moles of ethane will contain = 20.76 × 6 = 124.56 moles of Hydrogen atoms.
Therefore, 1.25×10²⁵ molecules of ethane contains 124.56 moles of Hydrogen atoms.
This is displacement reaction.
Enthalpy is the total heat content of a system.
<span> We are given with the rate constant of a first-order decomposition of n2o which is equal to 3.40 s-1. Half life of the radioactive material can be determined through the formula: t= ln2 /k where t is the half life of the material. t then upon substitution is equal to 0.2048 s. </span>
