<span>CH</span>₃<span>CH</span>₂<span>COOH + H</span>₂<span>O </span>↔ <span> CH</span>₃<span>CH</span>₂<span>COO</span>⁻<span> + H</span>₃<span>O</span>⁺<span>
</span>
pH = 0.5 pKa + 0.5 pCa
0.5 pCa = pH - 0.5 pKa
= 4.2 - (0.5 * (-log 1.34 x 10⁻⁵)) = 1.76
pCa = 3.53
Ca = antilog - 3.52 = 3 x 10⁻⁴
where Ca is the acid concentration
Answer:
Explanation:
2 Na+ 2 H2O → 2 NaOH + 1 H2
The answer to your question is green
3.46 g Cu 1 mol Cu 6.02*10^23 atoms Cu =
63.55 g Cu 1 mol Cu
3.28*10^22 atoms Cu
The one u clicked is the the right one