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3 years ago

Which of the following is an example of Newton's Third Law:

Physics

2 answers:

castortr0y [4]3 years ago

7 0

Uhh what the first answer says :)

sweet-ann [11.9K]3 years ago

4 0

Answer:

Examples of Newton's third law of motion are ubiquitous in everyday life. For example, when you jump, your legs apply a force to the ground, and the ground applies and equal and opposite reaction force that propels you into the air. Engineers apply Newton's third law when designing rockets and other projectile devices.

Explanation:

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Please help me with my science homework

Viktor [21]

For the "what is this investigation about", you could pick
the shape of the Earth, the size of the Earth, how the Sun
generates its energy, the distance to the Moon, why the
sky is blue ... things like that. There are millions uvum.

Trustworthy sources of information:
-- an Encyclopedia
-- a library book that's all about the subject of the investigation
-- a magazine that's all about exactly the subject of the investigation
-- a TV program that's ALL ABOUT the subject of the investigation
-- a teacher who teaches the subject of the investigation
-- a high school student whose hobby is the subject of the investigation
-- an adult whose hobby is the subject of the investigation
-- an adult whose JOB is the subject of the investigation
-- a high school student who got a very good grade in a course
where the subject of the investigation was taught
-- a college student who is studying the same subject as the investigation

UN-trustworthy sources of information:
(This doesn't mean that they're always wrong. It means that
they can tell you something, and you just can't be sure of
whether it's right or wrong.)
-- some sources listed on Google
-- some YouTube videos
-- other students in your class
-- other students at your school
-- your next-door neighbor (unless he's on the 'trustworthy' list above)
-- a newspaper article
-- a TV news item, or a TV program that's NOT all about the subject
-- a public opinion poll; (just because everybody thinks so
doesn't mean that it's true)
-- your sister's friend's hairdresser's grocer's mother-in-law
-- anything you hear if you don't know WHO said it

5 0

4 years ago

A cyclist intends to cycle up a 7.70o hill whose vertical height is 126m. Assuming the mass of bicycle plus person is 75.0kg, ca

Ksivusya [100]

Answer:

92704.5 J

596.44737 N

Explanation:

m = Mass of person + bicycle = 75 kg

g = Acceleration due to gravity = 9.81 m/s²

h = Vertical height = 126 m

$\theta$ = Angle = 7.7°

d = Diameter = 0.388 m

Work done against gravity is given by

$P=mgh\\\Rightarrow P=75\times 9.81\times 126\\\Rightarrow P=92704.5\ J$

Work done is 92704.5 J

Force required is given by

$F=\dfrac{mgrsin\theta}{\pi d}\\\Rightarrow F=\dfrac{75\times 9.81\times sin7.7\times 5.12}{\pi\times 0.388}\\\Rightarrow F=596.44737\ N$

The force is 596.44737 N

7 0

3 years ago

What is cheetah speed and strength?

pav-90 [236]

Answer:

Speed: 109.4–120.7 km/h (68.0–75.0 mph)

Strength: Couldn't find out.

Explanation:

3 0

3 years ago

Assume that the force of a bow on an arrow behaves like the spring force. In aiming the arrow, an archer pulls the drawstring ba

Alex

Answer:

v=39.05 m/s

Explanation:

Given that

x= 56 cm

F= 158 N

m= 58 g = 0.058 kg

Lets take spring constant = k

At the initial position,before releasing the arrow

F= k x

By putting the values

F= k x

158= 0.56 k

k=282.14 N/m

Now from energy conservation

Lets take final speed of the arrow after releasing

$\dfrac{1}{2}kx^2=\dfrac{1}{2}mv^2$

k x²=mv²

282.14 x 0.56² = 0.058 v²

v=39.05 m/s

3 0

3 years ago

Napoleon’s cannon, having a muzzle velocity of 333 m/s, is fired at a 0 degree angle off a cliff. The ball lands 622 m away from

timama [110]

The cannon is 17.69 m above the ground level

<h3>Data obtained from the question</h3>

The following data were obtained from the question:

Horizontal speed (u) = 333 m/s
Horizontal distance (s) = 622 m
Height (h) =?

<h3>How to determine the time </h3>

We'll begin by calculating the time taken for the ball to land on the ground. This can be obtained as follow:

Horizontal speed (u) = 333 m/s
Horizontal distance (s) = 622 m
Time (t) =?

s = ut

622 = 333 × t

Divide both sides by 333

t = 622 / 333

t = 1.9 s

<h3>How to determine the height</h3>

The height of the cannon above the ground can be obtained as illustrated below:

Acceleration due to gravity (g) = 9.8 m/s²
Time (t) = 1.9 s
Height (h) =?

h = ½gt²

h = ½ × 9.8 × 1.9²

h = 4.9 × 3.62

h = 17.69 m

Learn more about motion under gravity:

brainly.com/question/20385439

#SPJ1

3 0

1 year ago