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cluponka [151]
3 years ago
8

When you drop an object from a certain height, it takes time T to reach the ground with no air resistance. If you dropped it fro

m three times that height, how long (in terms of T) would it take to reach the ground?
Physics
1 answer:
alexandr402 [8]3 years ago
5 0

Answer:

Explanation:

Given

When we drop an object from height , suppose h

it takes time T

using equation of motion

h=ut+\frac{1}{2}at^2

where  

h=displacement

u=initial\ velocity

a=acceleration

t=time

here u=0 because it dropped from a certain height

h=\frac{1}{2}gT^2

T=\sqrt{\frac{2h}{g}}

When height is increases to three times of original height

i.e. h'=3 h

then time period becomes

T'=\sqrt{\frac{2\times 3h}{g}}

T'=\sqrt{3}T

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255 metres

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2 years ago
14. measuring cylinder containing some water stands on a scale pan. A solid ball is lowered into the water. The water level rise
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8 0
3 years ago
a body dropped from a height reaches a velocity of 13m/s just before touching the ground. What is the initial height of the ball
SashulF [63]

Hi there!

We can use the following (derived) equation to solve for the final velocity given height:

vf = √2gh

We can rearrange to solve for height:

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Plug in the given values (g = 9.81 m/s²)

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We can calculate time using the equation:

vf = vi + at, where:

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Plug in values:

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