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Setler [38]
3 years ago
5

NEED HELP ASAP TEST IS DUE TMR

Physics
1 answer:
JulijaS [17]3 years ago
8 0

Answer:

The answer should be uranus

Explanation:

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For a point charge, how does the potential vary with distance from the point charge, r?
mr_godi [17]

For a point charge, how does the potential vary with distance from the point charge, r?

a constant

b. r.

c. 1/r.

d. 1/r^2.

e. r^2.

Answer:

The  correct option is  C

Explanation:

Generally for a point charge the electric potential is mathematically represented as

    V  =  \frac{k  Q  }{r }

Here we can deduce that the electric potential varies inversely with the distance i.e

      V  \  \alpha \  \frac{1}{r}

So

   

3 0
3 years ago
Durning which type of process does pressure remain consistent
Simora [160]

Answer:

\fbox {D. Isobaric}

Explanation:

The process during which pressure remains constant is called an isobaric process.

6 0
2 years ago
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You push a desk with 230 N, but the desk doesn't move due to its friction with the ground. What is the magnitude of the friction
ASHA 777 [7]

Answer:

force \:  = friction \: based \: on \: newtons \: third \: law \\ \: f =  |230|  = 230 \: newton \\ this \: is \: why \: the \: desk \:  \\ doesnt \: move...

3 0
3 years ago
PLS HELP ASAP WILL MARK BRAIN and pls explain your answer....
lora16 [44]

Answer:

it is sublimation because There are three ways heat is transferred into and through the atmosphere:

radiation.

conduction.

convection.

Explanation:

please mark me as brainliest as you wrote over there

5 0
3 years ago
An astronaut weighs 8.00 × 102 newtons on the sur- face of Earth. What is the weight of the astronaut 6.37 × 106 meters above th
kolbaska11 [484]

Answer:

mg=200.4 N.

Explanation:

This problem can be solved using Newton's law of universal gravitation: F=G\frac{m_{1}m_{2}}{r^{2}},

where F is the gravitational force between two masses m_{1} and m_{2}, r is the distance between the masses (their center of mass), and G=6.674*10^{-11}(m^{3}kg^{-1}s^{-2}) is the gravitational constant.

We know the weight of the astronout on the surface, with this we can find his mass. Letting w_{s} be the weight on the surface:

w_{s}=mg,

mg=8*10^{2},

m=(8*10^{2})/g,

since we now that g=9.8m/s^{2} we get that the mass is

m=81.6kg.

Now we can use Newton's law of universal gravitation

F=G\frac{Mm}{r^{2}},  

where m is the mass of the astronaut and M is the mass of the earth. From Newton's second law we know that

F=ma,

in this case the acceleration is the gravity so

F=mg, (<u>becarefull, gravity at this point is no longer</u> 9.8m/s^{2} <u>because we are not in the surface anymore</u>)

and this get us to

mg=G\frac{Mm}{r^{2}}, where mg is his new weight.

We need to remember that the mass of the earth is M=5.972*10^{24}kg and its radius is 6.37*10^{6}m.

The total distance between the astronaut and the earth is

r=(6.37*10^{6}+6.37*10^{6})=2(6.37*10^{6})=12.74*10^{6} meters.

Now we can compute his weigh:

mg=G\frac{Mm}{r^{2}},

mg=(6.674*10^{-11})\frac{(5.972*10^{24})(81.6)}{(12.74*10^{6})^{2}},

mg=200.4 N.

5 0
3 years ago
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